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A 555 TImer has a R1 = 12k and R2 = 30k. For a capacitance of 1uF, find the values indicated: high pulse width: T1 = .693* (R1 + R2) C low pulse width: T2= .693 *(R2) C Period: sec (ROUND TO THE THIRD DECIMAL PLACE: 0.xxx) Frequency: Hz (ROUND TO THE WHOLE NUMBER: no decimal places) Duty Cycle: |(ROUND TO THE NEAREST PERCENT OR IF WRITING AS A DECIMAL, THE HUNDREDTHS PLACE)

A 555 TImer has a R1 = 12k and R2 = 30k. For a capacitance of 1uF, find the values indicated: high pulse width: T1 = .693* (R1 + R2) C low pulse width: T2= .693 *(R2) C Period: sec (ROUND TO THE THIRD DECIMAL PLACE: 0.xxx) Frequency: Hz (ROUND TO THE WHOLE NUMBER: no decimal places) Duty Cycle: |(ROUND TO THE NEAREST PERCENT OR IF WRITING AS A DECIMAL, THE HUNDREDTHS PLACE)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A 555 TImer has a R1 = 12k and R2 = 30k. For a capacitance of 1uF, find the values indicated: high pulse width: T1 = .693* (R1 + R2) C low pulse width: T2= .693 *(R2) C Period: sec (ROUND TO THE THIRD DECIMAL PLACE: 0.xxx) Frequency: Hz (ROUND TO THE WHOLE NUMBER: no decimal places) Duty Cycle: (ROUND TO THE NEAREST PERCENT OR IF WRITING AS A DECIMAL, THE HUNDREDTHS PLACE)
Transcribed Image Text:A 555 TImer has a R1 = 12k and R2 = 30k. For a capacitance of 1uF, find the values indicated: high pulse width: T1 = .693* (R1 + R2) C low pulse width: T2= .693 *(R2) C Period: sec (ROUND TO THE THIRD DECIMAL PLACE: 0.xxx) Frequency: Hz (ROUND TO THE WHOLE NUMBER: no decimal places) Duty Cycle: (ROUND TO THE NEAREST PERCENT OR IF WRITING AS A DECIMAL, THE HUNDREDTHS PLACE)
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