part B, please. **Physics Problem: Sprinting and Force Calculation**A 53 kg sprinter, starting from rest, runs 41 meters in 7.0 seconds with constant acceleration.**Part A: Force Calculation**- **Question:** What is the magnitude of the horizontal force acting on the sprinter? - **Answer Format:** Express your answer to two significant figures and include the appropriate units. - **Submitted Answer:** \( F_x = 89 \, \text{N} \) - **Feedback:** Correct. The calculated answer was 88.51 N, rounded to two significant figures.**Part B: Power Output Calculation**- **Question:** What is the sprinter’s power output at 2.0 seconds, 4.0 seconds, and 6.0 seconds? - **Answer Format:** Express your answers using two significant figures, separated by commas. - **Submitted Answers:** \( P(2.0), P(4.0), P(6.0) = 257, 128, 85.6 \, \text{kW} \) - **Feedback:** Incorrect. You have 5 attempts remaining to correct your answer.This exercise involves calculating the force acting on a sprinter using basic kinematic equations and examining the power output at specified time intervals.

Initial speed (u)= 0 Distance travel (s) = 41 m Time taken (t)= 7 S =ut + 1/2 at2 u = 0 a = 2s/t2 a = 2×41/49 a = 1.674 m/s2 So, acceleration is = 1.674 m/s2 Force (F) = mass × acceleration F = 53 × 1.674 F = 88.72 N Pwer (P) = Fs/t P(2) = 88.72×41/2 P(2) = 1818.76 watt P(2) = 1.82 kWP(4) = 88.72 × 41/4 P(4) = 909.38 watt P(4) = 0.91 kW And power at t = 6 seconds P(6) = 88.72 × 41/6 P(6) = 606.253 watt P(6) = 0.61 kW

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A 53 kg sprinter, starting from rest, runs 41 m in 7.0 s at constant acceleration. Part A What is the magnitude of the horizontal force acting on the sprinter? Express your answer to two significant figures and include the appropriate units. F, = 89 N Submit Previous Answers v Correct Correct answer is shown. Your answer 88.51 N was either rounded differently or used a different number of significant figure: Part B What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s? Express your answers using two significant figures separated by commas. ? P(2.0), P(4.0), P(6.0) = 257,128,85.6 kW Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining

A 53 kg sprinter, starting from rest, runs 41 m in 7.0 s at constant acceleration. Part A What is the magnitude of the horizontal force acting on the sprinter? Express your answer to two significant figures and include the appropriate units. F, = 89 N Submit Previous Answers v Correct Correct answer is shown. Your answer 88.51 N was either rounded differently or used a different number of significant figure: Part B What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s? Express your answers using two significant figures separated by commas. ? P(2.0), P(4.0), P(6.0) = 257,128,85.6 kW Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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parts b-e please.
For #1-4: Given : F₁= 200 N 30° above +x F₂= 200 N, 37° below +x 1. What are the components of F₁? a. x = 173.2 N, y = 100 N c. x = 17 N, y = 190 N b. x = 170 N, y = 90 N d. x = 1700 N, y = 1000 N 2. If the X component of F₂ is 159.7 N, what is its Y-component? a. -119 N b. 120.4 N d. 121.4 N c. -120.4 N 3. What is the magnitude and direction of the resultant force? a. 332.56 N 2.8° below +x b. 323.65 N 3.0° above +x 4. In what direction is F₂ heading? a. 37° below +x b. 35° below-x c. 36° above +x d. 53° below -X c.332.56 N, 3.5° below +x d. 332.56 N, 2.6° below-x
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