A 5,000-liter tank initially contains 1,100 liters of water with 1.2- kg of salt dissolved in it. Water enters the tank at a rate of 0.40 li/min and the water entering the tank has a salt concentration of (1+ cos t) kg/li. If a well mixed solution leaves the tank at a rate of 0.20 li/min, how much salt is in the tank when it overflows?

Q: 2 +,

A:

Q: x² ,2 xp V16-x2

A:

Q: n-6=5

A: Here we have to find the value of n =?  3n-6=5n

Q: V24x15y5 3

A:

Q: 1n+2

A: We need to find : ∫1n+1n dn

Q: 5v2 +6 dv 4 v3

A:

Q: 23-8K

A:

Q: Consider F(x) = = F(0) = 0 F'(3) = 6 F'(1) = 0 O F'(4) = 10 F'(2) = 2 I tf(t) tf(t) dt. Which of the…

A:

Q: X+2y=3 , x-y=6

A:

Q: dt t2-t-6

A:

Q: 3a+4b=5a-t

A: See this solution in below.

Q: (4x)2

A: To evaluate(4x)2

Q: 9x+4y=13 3x+5y=9

A:

Q: xy dxdy Hw

A: See attached file for a step by step explanation.

Q: 9x4 y4  x  x2  y2

A: Given:  9x4y4 × x2y2

Q: 4x+y+2y

A: We can use normal algebra to solve this problem.

Q: 2: Find: L-1[: 1 3 - 3]

A:

Q: V3 + V75 = V3 + V25 -3 = v3 + V3 =

A: Given expression to simplify: 3+75

Q: 4т V17 3

A: Modulus function always gives positive quantity in result.

Q: V6x + 7 – 2 = x

A:

Q: w+5 -dw w - 6w+10

A: A detailed solution is given below

Q: 2a+3a=c

A:

Q: 4 5x2 Evaluate dx. TV3x2-1

A:

Q: 3+2x2x

A:

Q: Y+5>1

A: I am going to solve the given problem by using some simple algebra to get the required result.

Q: a + 4e + 5d+ 3a

A: We will simplify the given expression.     8a+4e+5d+3a=11a+4e+5d

Q: 3x- 13x +4= 0

A:

Q: 4h aー-5

A: We have to find out

Q: X+3y=9

A: this is a two variable linear equation X + 3Y = 9

Q: y +y - 2y = 0

A: Here we have to solve , the given differential equation  y"+y'-2y=0 ...........(1)

Q: -3a + 12a

A: -3a+12a=9a