A 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2C to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H* = 3 12 + 6 K* + 3 H20 C6H8O6 + 12 = C6H606 + 21 + 2H* 3.39 % 33.89 % 67.77 %
A 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2C to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H* = 3 12 + 6 K* + 3 H20 C6H8O6 + 12 = C6H606 + 21 + 2H* 3.39 % 33.89 % 67.77 %
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.34E
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you