A 500 g sample of aluminum sulfate is reacted with 450 grams of calcium hydroxide. A total of 596 g of calcium sulfate is produced when the experiment is carried out in real lab conditions. Which method below would correctly determine the limiting reactant? Al2(SO4)3 (aq) +3 Ca(OH)2 (aq) --> 2 Al(OH)3 (s) + 3 CaSO4 (s) Convert 500g of aluminum sulfate into aluminum hydroxide. Convert 450 grams of calcium hydroxide into calcium sulfate. The reactant that makes the
A 500 g sample of aluminum sulfate is reacted with 450 grams of calcium hydroxide. A total of 596 g of calcium sulfate is produced when the experiment is carried out in real lab conditions. Which method below would correctly determine the limiting reactant?
Al2(SO4)3 (aq) +3 Ca(OH)2 (aq) --> 2 Al(OH)3 (s) + 3 CaSO4 (s)
Convert 500g of aluminum sulfate into aluminum hydroxide. Convert 450 grams of calcium hydroxide into calcium sulfate. The reactant that makes the least amount of the product they match best is the limiting reactant.
Convert 500g of aluminum sulfate into aluminum hydroxide, then convert 450 grams of calcium hydroxide into aluminum hydroxide. The reactant that would produce the least when compared to the same product is the limiting reactant.
Cannot be determined from the information provided.
Convert both 500g of aluminum sulfate and 450 g of calcium hydroxide to calcium sulfate. The one that makes exactly 596 g is the limiting reactant.
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