A 50.0 mA current is carried by a uniformly wound air-core solenoid with 400 turns, a 15.0 mm diameter, and a 12.0 cm length. Calculate the magnetic field inside the solenoid.
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A: Givens, n=Nl=8×103B→=0.032T
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Q: magnetic field of the solenoid
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Q: An electromagnet is made by inserting a soft iron core into a solenoid. The solenoid has 1800 turns,…
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Q: S - Pm The magnetic flux through the loop shown in the accompanying figure varies with time…
A: Given,ϕm=ϕ0 e-αt sinωt ----(1)where,ϕ0=5×10-3 T m2α = 4 s-1.ω=120 π rad/s.R=5 Ω.The magnitude and…
Q: The figure below shows an end view of a single-turn square loop of metal wire in the center of and…
A: Given: Length of solenoid, L=23 cm=0.23 m Radius of loop, r=3 cm=0.03 m Number of turns of wire,…
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A: From the question we are told that The current is I=7.37A The length is L=10.0 cm=0.1 m The magnetic…
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A: Solution: To solve this problem, we can use the formula for the resistance of a solenoid: R = (4 *…
Q: A solenoid contains 700 loops has a diameter of 6 cm and a length of 15 cm. What is the magnetic…
A: Magnetic field created at the center of the solenoid:B=μ0NILwhere, μ0=1.26 × 10-6 T·m/AN=700L=15…
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A: The energy density is 55.1 J/m3.
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A: N = 4927 turns L = 67.3 cm I = 11.1 A
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Q: A long solenoid that has 820 turns uniformly distributed over a length of 0.390 m produces a…
A: Given Data: Number of turns N=820 Length L=0.390 m Magnetic field B=1.00×10-4T To Find: Current in…
Q: Assuming the Earth's magnetic field averages about 0.50×10−4 T near Earth's surface, estimate the…
A: Consider the magnetic field of Earth is denoted by B, Earth’s radius is denoted by R and R’ is the…
Q: A very long solenoid with a circular cross section and radius r= 5.10 cm with n= 1.10E+4 turns/m has…
A: r = 5.10 cm = 0.0510 m n = 1.10 x 104 turns/m uB = 6.60 mJ/m3 = 6.60 x 10-3 J/m3 L = 0.620 m I = ?
Q: MIT Francis Bitter Magnetic Laboratory has achieved a magnetic field of 37.2 T (as of 2004). Find…
A: Given values:- Magnetic field,(B)=37.2 T -----(1) Radius of solenoid,(r)=2.40 cm=2.40 x 10-2 m…
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- As a new electrical technician, you are designing a large solenoid to produce a uniform 0.120-T magnetic field near the center of the solenoid. You have enough wire for 4000 circular turns. This solenoid must be 55.0 cm long and 2.80 cm in diameter. What current will you need to produce the necessary field? Express your answer to three significant figures and include the appropriate units.An air-core solenoid with 64 turns is 8.00 cm long and has a diameter of 1.20 cm. When the solenoid carries a current of 0.780 A, how much energy is stored in its magnetic field?A 2278 turn solenoid is carrying a current of 18.2 A. The solenoid is 98.45 cm long. What is the magnitude of the magnetic field (in milli-tesla) through the center of the solenoid?
- 8. An electromagnet is made by inserting a soft iron core into a solenoid. The solenoid has 1800 turns, radius 2.00 cm, and length 23.5 cm. When 2.00 A of current flows through the solenoid, the magnetic field inside the iron core has magnitude 0.920 T. What is the relative permeability κB of the iron core?A 59.0 cm -long solenoid 1.35 cm in diameter is to produce a field of 0.395 mT at its center. How much current should the solenoid carry if it has 790 turns of wire?You have a solenoid with an initial current of 386 A and a turn density of 6088 What is the initial magnetic field through the solenoid? Binitial = 2.95 T The current in the solenoid drops to 51 A over the course of 1.1 ms. What is the final magnetic field through the solenoid? Bfinal = T Inside the solenoid is a coil with 75 loops and a radius of 9.0 cm. The coil is aligned so that the magnetic field from the solenoid passes through the coil perpendicular to the plane of the coil (directly down the center of the coil). What is the magnitude of the induced emf in the 75-turn coil at the center of the solenoid during this change in magnetic field? Enter you answer as a positive number. emf = V The coil has a resistance of 20 2. What is the current through the coil? Icoil A loops m = What is the power dissipated by the coil? Pcoil = W