A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m
A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding
friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively.
3.00 m
64.1 kN
25.7 kN
24.1 KN
19.24 KN
C
q
B
2. Which of the following equilibrium equations is INCORRECT?
3.00 m
D
A
45.0°
P₁ = 20.0 kN
P2 = 10.00 KN
1.000 m
A: ΣFx = P₁ cos 45 + P₂ - f = 0
B:
ΣFy=N-W-P₁
sin 45 = 0
C: +UM₁ = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) – P₂(1) – Nx = 0
D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3-x) = 0
3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground?
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