ANSWER IN 20 MINS A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonslidingfriction and sliding friction between the container and the ground is 0.400 and 0.300 respectively.3.00 m64.1 kN25.7 kN24.1 KN19.24 KNCqB2. Which of the following equilibrium equations is INCORRECT?3.00 mDA45.0°P₁ = 20.0 kNP2 = 10.00 KN1.000 mA: ΣFx = P₁ cos 45 + P₂ - f = 0B:ΣFy=N-W-P₁sin 45 = 0C: +UM₁ = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) – P₂(1) – Nx = 0D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3-x) = 03. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground?

Answered: Image /qna-images/answer/b86f57ff-4b4e-40ec-9627-cd25598130ac.jpg

A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m

A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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