A 50.0-kg block is being pulled up a 16.0° slope by a force of 250 N that is parallel to the slope. The coefficient of kinetic friction between the block and the slope is 0.200. I have the answers, I do not know how to get them. a. What is the acceleration of the block? a = 0.415 m/s2 up the incline b. The same block is now pushed up the slope with a 300N force perfectly horizontally. What i the acceleration of the block now? a = 0.851 m/s2 up the incline c. If there was a scale placed under the block as it was pushed as in (b), what would the scale read? Fscale 553.7N

icon
Related questions
Question

Plz solve within 30min I vill give definitely upvote and vill give positive feedback thank you sir 

A 50.0-kg block is being pulled up a 16.0° slope
by a force of 250 N that is parallel to the slope.
The coefficient of kinetic friction between the
block and the slope is 0.200.
I have the answers, I do not know how to get
them.
a. What is the acceleration of the block?
a = 0.415 m/s2 up the incline
b. The same block is now pushed up the slope
with a 300N force perfectly horizontally. What is
the acceleration of the block now?
a = 0.851 m/s2 up the incline
c. If there was a scale placed under the block as
it was pushed as in (b), what would the scale
read?
Fscale = 553.7N
Transcribed Image Text:A 50.0-kg block is being pulled up a 16.0° slope by a force of 250 N that is parallel to the slope. The coefficient of kinetic friction between the block and the slope is 0.200. I have the answers, I do not know how to get them. a. What is the acceleration of the block? a = 0.415 m/s2 up the incline b. The same block is now pushed up the slope with a 300N force perfectly horizontally. What is the acceleration of the block now? a = 0.851 m/s2 up the incline c. If there was a scale placed under the block as it was pushed as in (b), what would the scale read? Fscale = 553.7N
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 2 images

Blurred answer