A 5.340 kg5.340 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is us=0.455μs=0.455 and the coefficient of kinetic friction is uk=0.155.pk-0.155. At time t=0,t=0, a force F-14.7 NF-14.7 N is applied horizontally to the block. State the force of friction applied to the block by the table at times t=0t=0 and t>0 Consider the same situation, but this time the external force FF is 29.6 N.29.6 N. Again, state the force of friction acting on the block at times t=0t=0 and t>0.
A 5.340 kg5.340 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is us=0.455μs=0.455 and the coefficient of kinetic friction is uk=0.155.pk-0.155. At time t=0,t=0, a force F-14.7 NF-14.7 N is applied horizontally to the block. State the force of friction applied to the block by the table at times t=0t=0 and t>0 Consider the same situation, but this time the external force FF is 29.6 N.29.6 N. Again, state the force of friction acting on the block at times t=0t=0 and t>0.
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![A 5.340 kg5.340 kg block of wood rests on a steel desk. The
coefficient of static friction between the block and the desk is
μs=0.455µs=0.455 and the coefficient of kinetic friction is
µk=0.155.µk=0.155. At time t=0,t=0, a force F=14.7 NF=14.7 N is
applied horizontally to the block. State the force of friction applied
to the block by the table at times t=0t=0 and t>0
Consider the same situation, but this time the external force FF is
29.6 N.29.6 N. Again, state the force of friction acting on the block
at times t=0t=0 and t>0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d0c8e0-9057-4435-b967-ab610bba04e8%2F2a0cb6cf-b334-427d-9c0c-a631af9f042b%2Fqi8tecg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 5.340 kg5.340 kg block of wood rests on a steel desk. The
coefficient of static friction between the block and the desk is
μs=0.455µs=0.455 and the coefficient of kinetic friction is
µk=0.155.µk=0.155. At time t=0,t=0, a force F=14.7 NF=14.7 N is
applied horizontally to the block. State the force of friction applied
to the block by the table at times t=0t=0 and t>0
Consider the same situation, but this time the external force FF is
29.6 N.29.6 N. Again, state the force of friction acting on the block
at times t=0t=0 and t>0.
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