A 5.29 kg ball is attached to the top of a vertical pole with a 2.19 m length of massless string. The ball is struck, causing it to revolve around the pole at a speed of 4.35 m/s in a horizontal circle with the string remaining taut. Calculate the angle 0, between 0° and 90°, that the string makes with the pole. Use g = 9.81 m/s². 0 = What is the tension T of the string? T= N

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Chapter14: Fluid Mechanics
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A 5.29 kg ball is attached to the top of a vertical pole with a
2.19 m length of massless string. The ball is struck, causing it
to revolve around the pole at a speed of 4.35 m/s in a
horizontal circle with the string remaining taut. Calculate the
angle 0, between 0° and 90°, that the string makes with the
pole. Use g = 9.81 m/s².
0 =
What is the tension T of the string?
T =
N
Transcribed Image Text:Macmillan Learning A 5.29 kg ball is attached to the top of a vertical pole with a 2.19 m length of massless string. The ball is struck, causing it to revolve around the pole at a speed of 4.35 m/s in a horizontal circle with the string remaining taut. Calculate the angle 0, between 0° and 90°, that the string makes with the pole. Use g = 9.81 m/s². 0 = What is the tension T of the string? T = N
< Question 21 of 25 >
O Macmillan Learning
An object of mass m₁ = 0.105 kg undergoes uniform circular
motion. It is connected by a massless string through a hole in
a frictionless table to a larger object of mass m₂ = 0.275 kg,
as shown in the figure. Assuming the larger object is
stationary, calculate the tension T in the string and the linear
speed u of the circular motion of the smaller object on the
table. Assume that the radius R of the circular path of the
smaller object is equal to 1.00 m.
T =
V =
N
m/s
Transcribed Image Text:< Question 21 of 25 > O Macmillan Learning An object of mass m₁ = 0.105 kg undergoes uniform circular motion. It is connected by a massless string through a hole in a frictionless table to a larger object of mass m₂ = 0.275 kg, as shown in the figure. Assuming the larger object is stationary, calculate the tension T in the string and the linear speed u of the circular motion of the smaller object on the table. Assume that the radius R of the circular path of the smaller object is equal to 1.00 m. T = V = N m/s
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