A 5-card hand is dealt from a standard 52-card deck. If the 5-card hand contains at least one ace, you win $11; otherwise, you lose $1. What is the expected value of the game? dollars. The expected value of the game is (Type an integer or a decimal rounded to two decimal places.)

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A 5-card hand is dealt from a standard 52-card deck. If the 5-card hand contains at least one ace, you win $11; otherwise, you lose $1.
What is the expected value of the game?
dollars.
The expected value of the game is
(Type an integer or a decimal rounded to two decimal places.)
Transcribed Image Text:A 5-card hand is dealt from a standard 52-card deck. If the 5-card hand contains at least one ace, you win $11; otherwise, you lose $1. What is the expected value of the game? dollars. The expected value of the game is (Type an integer or a decimal rounded to two decimal places.)
Expert Solution
Step 1

In a deck of 52 cards we have 4 ace cards.

The probability of no ace card is computed as,

P(No ace card)=C548C552                            =48!43!×5!52!47!×5!                            =0.658842

Thus,

P(at least one ace card) = 1- P(No ace card)

                                      = 1-0.658842

                                      = 0.341158.

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