A 4830-kg car enters an 7.6-percent downhill grade at a speed of 103 km/h. The driver applies her brakes to bring the car to a speed of 20 km/h in a distance of 0.49 km measured along the road. Calculate the energy loss Q (enter as a positive number) dissipated from the brakes in the form of heat. Neglect any friction losses from other causes such as air resistance. Answer: Q = i kJ

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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A 4830-kg car enters an 7.6-percent downhill grade at a speed of 103 km/h. The driver applies her brakes to bring the car to a speed of
20 km/h in a distance of 0.49 km measured along the road. Calculate the energy loss Q (enter as a positive number) dissipated from the
brakes in the form of heat. Neglect any friction losses from other causes such as air resistance.
Answer: Q = i
kJ
Transcribed Image Text:A 4830-kg car enters an 7.6-percent downhill grade at a speed of 103 km/h. The driver applies her brakes to bring the car to a speed of 20 km/h in a distance of 0.49 km measured along the road. Calculate the energy loss Q (enter as a positive number) dissipated from the brakes in the form of heat. Neglect any friction losses from other causes such as air resistance. Answer: Q = i kJ
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