A 460-V, 25-hp, 60-Hz, four pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: R1 = 0.6410 R2 = 0.3320 %3D X2 = 0.4640 The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 2.2 % at the rated voltage and rated frequency, find the motor's X1 1.106N XM = 26.30 %3D d) Pcony and Pout
A 460-V, 25-hp, 60-Hz, four pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: R1 = 0.6410 R2 = 0.3320 %3D X2 = 0.4640 The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 2.2 % at the rated voltage and rated frequency, find the motor's X1 1.106N XM = 26.30 %3D d) Pcony and Pout
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:A 460-V, 25-hp, 60-Hz, four pole, Y-connected induction motor has the
following impedances in ohms per phase referred to the stator circuit:
R1 = 0.6410
R2
= 0.3320
X = 1.1060
X2 = 0.4640
Хм — 26.30
The total rotational losses are 1100 W and are assumed to be constant.
The core loss is lumped in with the rotational losses. For a rotor slip of
2.2 % at the rated voltage and rated frequency, find the motor's
e) Tina and Tioad
f) Efficiency

Transcribed Image Text:A 460-V, 25-hp, 60-Hz, four pole, Y-connected induction motor has the
following impedances in ohms per phase referred to the stator circuit:
R1 = 0.6410
R2
0.3320
%3D
X = 1.1060
X2
= 0.464N
Хм — 26.30
%3D
%3D
The total rotational losses are 1100 W and are assumed to be constant.
The core loss is lumped in with the rotational losses. For a rotor slip of
2.2 % at the rated voltage and rated frequency, find the motor's
d) Pconv and Pout
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