A 45.0-cm diameter disk rotates with a constant angular accelerationof 2.50 rad/s2. It starts from rest at t 5 0, and a linedrawn from the center of the disk to a point P on the rim of thedisk makes an angle of 57.3° with the positive x - axis at this time.At t = 2.30 s, find (a) the angular speed of the wheel, (b) thelinear speed and tangential acceleration of P, and (c) the positionof P (in degrees, with respect to the positive x - axis).
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
A 45.0-cm diameter disk rotates with a constant angular acceleration
of 2.50 rad/s2. It starts from rest at t 5 0, and a line
drawn from the center of the disk to a point P on the rim of the
disk makes an angle of 57.3° with the positive x - axis at this time.
At t = 2.30 s, find (a) the angular speed of the wheel, (b) the
linear speed and tangential acceleration of P, and (c) the position
of P (in degrees, with respect to the positive x - axis).
Trending now
This is a popular solution!
Step by step
Solved in 5 steps with 4 images