A 44.00 mL mixture containing 0.0631 M TI* and 0.0631 M Hg3+ is titrated with 0.0877 M NaI resulting in the formation of the precipitates TII and Hg,I,. Calculate pI¯ at the given points in the titration. The Kp values for TII and Hg,I, are 5.54 × 10-8 and 2.9 × 10-29 , respectively. 46.8 mL pl = 78.2 mL pl- = second equivalence point pI¯ = %3D 103.2 mL pI¯ = %3D

A 44.00 mL mixture containing 0.0631 M TI* and 0.0631 M Hg3+ is titrated with 0.0877 M NaI resulting in the formation of the precipitates TII and Hg,I,. Calculate pI¯ at the given points in the titration. The Kp values for TII and Hg,I, are 5.54 × 10-8 and 2.9 × 10-29 , respectively. 46.8 mL pl = 78.2 mL pl- = second equivalence point pI¯ = %3D 103.2 mL pI¯ = %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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