A 4.0-2 resistor is connected to a 12-2 resistor and this combination is connected to an ideal dc power supply with voltage V = 12 volts as shown in the figure. What is the value of current in the 12- resistor? O 1 A O 3 A O 12 A O 15 A 4 A 4.00 www www 12 Ω

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**Problem Statement:**
A 4.0-Ω resistor is connected to a 12-Ω resistor and this combination is connected to an ideal DC power supply with voltage \( V = 12 \) volts as shown in the figure. What is the value of current in the 12-Ω resistor?

**Diagram Explanation:**
The diagram shows a circuit with a 4.0-Ω resistor and a 12-Ω resistor connected in parallel to each other. This parallel combination is connected to a DC power supply of 12 volts. Current \( I \) flows from the voltage source, splitting at the junction before the resistors.

**Solution Options:**
- ○ 1 A
- ○ 3 A
- ○ 12 A
- ○ 15 A
- ○ 4 A

**Analysis:**
To find the current through the 12-Ω resistor, we can use the formula for current in a parallel circuit and Ohm's Law (\( V = IR \)).

1. Calculate the total resistance in parallel:
   \[
   \frac{1}{R_{\text{total}}} = \frac{1}{4} + \frac{1}{12}
   \]

   Solving for \( R_{\text{total}} \):
   \[
   R_{\text{total}} = \frac{1}{\left( \frac{1}{4} + \frac{1}{12} \right)} = \frac{1}{\frac{1+3}{12}} = \frac{12}{4} = 3 \, \text{Ω}
   \]

2. Calculate the total current from the power supply:
   \[
   I_{\text{total}} = \frac{V}{R_{\text{total}}} = \frac{12 \, \text{V}}{3 \, \text{Ω}} = 4 \, \text{A}
   \]

3. Current through the 12-Ω resistor:
   Using the current divider rule:
   \[
   I_{12 \, \text{Ω}} = I_{\text{total}} \times \frac{R_{\text{other}}}{R_{\text{total}}} = 4 \, \text{A} \times \frac{4}{3}
   \]

   \[
   I_{12 \, \text{Ω}} = \
Transcribed Image Text:**Problem Statement:** A 4.0-Ω resistor is connected to a 12-Ω resistor and this combination is connected to an ideal DC power supply with voltage \( V = 12 \) volts as shown in the figure. What is the value of current in the 12-Ω resistor? **Diagram Explanation:** The diagram shows a circuit with a 4.0-Ω resistor and a 12-Ω resistor connected in parallel to each other. This parallel combination is connected to a DC power supply of 12 volts. Current \( I \) flows from the voltage source, splitting at the junction before the resistors. **Solution Options:** - ○ 1 A - ○ 3 A - ○ 12 A - ○ 15 A - ○ 4 A **Analysis:** To find the current through the 12-Ω resistor, we can use the formula for current in a parallel circuit and Ohm's Law (\( V = IR \)). 1. Calculate the total resistance in parallel: \[ \frac{1}{R_{\text{total}}} = \frac{1}{4} + \frac{1}{12} \] Solving for \( R_{\text{total}} \): \[ R_{\text{total}} = \frac{1}{\left( \frac{1}{4} + \frac{1}{12} \right)} = \frac{1}{\frac{1+3}{12}} = \frac{12}{4} = 3 \, \text{Ω} \] 2. Calculate the total current from the power supply: \[ I_{\text{total}} = \frac{V}{R_{\text{total}}} = \frac{12 \, \text{V}}{3 \, \text{Ω}} = 4 \, \text{A} \] 3. Current through the 12-Ω resistor: Using the current divider rule: \[ I_{12 \, \text{Ω}} = I_{\text{total}} \times \frac{R_{\text{other}}}{R_{\text{total}}} = 4 \, \text{A} \times \frac{4}{3} \] \[ I_{12 \, \text{Ω}} = \
Expert Solution
Step 1

Given:-

Resistance of the resistors are R1=4 Ω, R2=12Ω

Voltage of the supply source is V=12 V

Required:-

Current through the 12Ω resistor.

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