A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.) Complete the Laplace transform of the differential equation. s² L{x} + sL{x}= + Use the Laplace transform to find the equation of motion x(t). x(t) = + [ ) L{x} = ( 0

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.7: Exponential And Logarithmic Models
Problem 4SE: Define Newton’s Law of Cooling. Then name at least three real-world situations where Newton’s Law of...
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DIFFERENTAL EQUATION


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A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a
damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.)
8
Complete the Laplace transform of the differential equation.
s² L{x} +
]] )s£{x} + [
Use the Laplace transform to find the equation of motion x(t).
x(t) =
L{x} = 0
Transcribed Image Text:A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.) 8 Complete the Laplace transform of the differential equation. s² L{x} + ]] )s£{x} + [ Use the Laplace transform to find the equation of motion x(t). x(t) = L{x} = 0
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