A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.) Complete the Laplace transform of the differential equation. s² L{x} + sL{x}= + Use the Laplace transform to find the equation of motion x(t). x(t) = + [ ) L{x} = ( 0
A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.) Complete the Laplace transform of the differential equation. s² L{x} + sL{x}= + Use the Laplace transform to find the equation of motion x(t). x(t) = + [ ) L{x} = ( 0
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DIFFERENTAL EQUATION
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![A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a
damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.)
8
Complete the Laplace transform of the differential equation.
s² L{x} +
]] )s£{x} + [
Use the Laplace transform to find the equation of motion x(t).
x(t) =
L{x} = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F929ee3bc-b1ad-4e12-8ae1-a98e24d5b872%2Fcb0fbc1d-b491-4c30-9a49-7ded34c42556%2F6w1tut_processed.png&w=3840&q=75)
Transcribed Image Text:A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a
damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.)
8
Complete the Laplace transform of the differential equation.
s² L{x} +
]] )s£{x} + [
Use the Laplace transform to find the equation of motion x(t).
x(t) =
L{x} = 0
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