A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? O a) d = rad/s 4√5 b) de = rad/s 2√7 = rad/s 4√7 d) = -√rad/s

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide
down the wall.
If 0 is the angle that the bottom of the ladder makes with the ground, what is the
rate of change
of this angle (in radians per second) if the top of the ladder is sliding down the wall at
a rate of
0.25 m/s, when the top of the ladder is 3 m above the ground?
a) dt =
4/5 rad/s
4√5
b) = -√rad/s
=
rad/s
4√7
Od)=-rad/s
==
Transcribed Image Text:A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? a) dt = 4/5 rad/s 4√5 b) = -√rad/s = rad/s 4√7 Od)=-rad/s ==
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