A 3kg block it’s on a horizontal table top connected by a rope and pulley to a 2kg mass. If the system it’s accelerating at a 2.5 m/s^2. What is the tension in the rope and coefficient of friction? Please use the equations provided. **Equations****Vector Components, Standard Cartesian Plane:**- \( V_x = V \cos \theta \)- \( V_y = V \sin \theta \)- \( V_x^2 + V_y^2 = V^2 \)- \( \tan \theta = V_y/V_x \)**Constant Linear Acceleration:**- \( v = v_0 + at \)- \( d = d_0 + v_0t + \frac{1}{2} at^2 \)- \( v^2 = v_0^2 + 2a(d - d_0) \)**Projectile Motion:**- \( x = x_0 + v_{0x}t \)- \( y = y_0 + v_{0y} - \frac{1}{2} gt^2 \)- \( v_y = v_{0y} - gt \)**Rotational Motion:**- \( 360^\circ = 2 \pi \) radians- \( \theta = s/r \)- \( \omega = v/r \)- \( \alpha = a_T/r \)- \( a_c = v^2/r = r\omega^2 \)- \( \omega = \omega_0 + \alpha t \)- \( \theta = \theta_0 + \omega_0 t + \frac{1}{2} \alpha t^2 \)- \( \omega^2 = \omega_0^2 + 2\alpha(\theta - \theta_0) \)**Newton's Second Law of Motion:**- \( \Sigma \vec{F} = m\vec{a} \)**Gravitational Force, or Weight:**- \( F_g = mg \)**Frictional Force:**- \( F_f = \mu F_n \)**Centripetal Force:**- \( F_c = mv^2/r \)Use \( g = 10.0 \, \text{m/s}^2 \) for the acceleration due to gravity near the surface of the Earth.

Name: A 3kg block it’s on a horizontal table top connected by a rope and pul
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: A 3kg block it’s on a horizontal table top connected by a rope and pulley to a 2kg mass. If the system it’s accelerating at a 2.5 m/s^2. What is the tension in the rope and coefficient of friction? Please use the equations provided. **Equations****Ve