A 350g sample of aluminum is taken out of the freezer at –20oC and placed into 500g of water at 14.6 oC.  If the water and the aluminum both end up at 10 oC, what is the specific heat of aluminum? hint: since the heat lost by the water equals the heat gained by the aluminum, you can set up the equation as follows:  mass water × ΔTwater × C water = - mass metal × ΔTmetal × c metal

Q: A 6.57 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: A 7.37 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: A 4.79 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: Calorimetry is the easiest way to calculate the amount of heat transfer to a substance or from a…

Q: A 1753 kg1753 kg car is traveling down the road at 82.2 km/h.82.2 km/h. While traveling at this rate…

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Q: What is the specific heat of tin if a 55.0-g sample absorbs 982 J of heat to raise its temperature…

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Q: 4.33g sample of an unknown salt (MM=116.83g/mol) is dissolved in 150.00g water coffee cup…

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Q: A 7.03 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: We know during the process of any reaction, heat gained  = heat lost . For above the formula used…

Q: The specific heat of a substance is the amount of heat required to raise the temperature of one gram…

A: Given --> Q = 357 J  S = 0.362 J/g°C T1 = 24.1°C T2 = 80.6°C

Q: If 63.50 g of an unknown metal at 97.6 °C initially produced a resulting temperature of 39.5 °C when…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 2. What is the specific heat of a metal whose mass is 94.5 g and the temperature changes from 48 °C…

A: Consider the given information is as follows; Mass of the metal = 94.5 g Initial temperature T1…

Q: An unknown metal with a specific heat of 0.385j has an initial temperature of 65.4 C. the metal is…

A: The heat absorbed or released by the Substance related with each other by following formula -   M1…

Q: metal radiator is made from 25.9 kg of iron. The specific heat of iron is 0.449 J/g °C. How much…

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Q: A sample of iron absorbs 62.3 J of heat, upon which the temperature of the sample increases from…

A: The amount of heat required is related to specific heat capacity as,…

Q: 2. What is the specific heat of Silicon if the temperature of a 41.1 g sample is increased by 34.1°C…

A: Thermodynamics is branch of chemistry in which we deal with amount of heat evolved or absorbed by…

Q: A calorimeter has a negligible heat capacity. It contains 52.3 g of water initially at 22.4 Celsius.…

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Q: A 225-g sample of aluminum was heated to 125.5 oC, then placed into 500.0 g water at 22.5 oC. (The…

A: Here we have:           mass of aluminiun, mAl = 225 g             mass of water , mH2O = 500.0 g…

Q: What is the specific heat of aluminum if the temperature of a 28.4 g sample of aluminum is increased…

A: The specific heat of a substance is defined as the amount of heat required to raise the temperature…

Q: When hydrogen and oxygen are burned to produce water, heat is produced at the rate of 58 kcal/mole…

A: Given, 1 mol H2O = 6.022 ×1023 molecules  Heat produced = 58 Kcal/mol

Q: 4. What is the specific heat of iron, if it requires 1050 J of heat energy to raise the temperature…

A: Heat required = 1050 J Initial temperature = 10.0°C Final temperature= 20.4°C Change in temperature…

Q: When hydrogen and oxygen are burned to produce water, heat is produced at the rate of 58 kcal/mole…

A: Given: Heat produced per mole of water = 58 Kcal/mol of water. And 1 mole of water contains = 6.02 ×…

Q: A 440.0 g quantity of a certain metal is heated to 100.0 C. It is immediately placed into 258 g of…

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Q: A 4.35 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: The heat released or absorbed (q) when the temperature of any substance is raised is calculated as:…

Q: 6. If 53.2 g Al solid at 120.0 °C is placed in 110.0 g H₂O at 90 °C within an insulated container…

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Q: What is the heat capacity of 265 grams of water? The specific heat of water is 4.184 J/g °C.

A: • The values provided in the question are:-  i) Mass of water, m = 265 g  ii) Specific heat capacity…

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Q: 1.64 L of hydrochloric acid are mixed with 735 mL of ammonia in a calorimeter. The initial…

A: Solution - According to the question - Given - 1.64 L = 1.64 * 10000 = 1640 ml Total volume = 1640 +…

Q: A chemical reaction is carried out in a 30.0 g calorimeter. The calorimeter has a specific heat of…

A: Here the heat released by the reaction is absorbed by both the calorimeter and water inside the…

Q: A solution is made by mixing 197.3 g of ethanol initially at 10.5°C with 250.0 g of water initially…

A: We know that, according to the law of conservation of heat energy, energy gained or loss by the…

Q: A piece of metal with a specific heat of 1.09 J/gºC is heated to 108ºC and then placed in 139.785 g…

A: Given that: Mass of water = 139.785 gInitial temperature of water = 1.7oCFinal temperate of water…

Q: A 22.0 g sample of pure iron at 85 °C is dropped into 73 g of water at 20. °C. What is the final…

A: Mass of pure iron sample = 22.0 g Initial temperature of pure iron sample = 85o C  Mass of water =…

Q: 7. 200g of copper is placed in an oven. The hot metal is removed from the oven and quickly added to…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 161.0 g sample…

A: A chemist carefully measures the amount of heat needed to raise the temperature of a 161.0 g sample…

Q: A metal object with mass of 20.5 g is heated to and then transferred to an insulated container…

A: when we mix to object then it grow from high temperature too low temperature . so apply principle of…

Q: When immersed in water, the temperature of a 102.1 gram sample of metal changes from 150.2 0C to…

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Q: he specific heat of a substance is the amount of heat required to raise the temperature of one gram…

A: The formula to find heat released or absorbed in calorimetry is: Q = m * s * ∆T  where m = mass of…

Q: A piece of hot metal, X, weighs 24.50 g.  After heating in a steam bath at 100.0oC, it is plunged…

A: The principle used here is Heat loss by metal = heat gained by water

Q: heat, upon which the temperature of the sample increases from 21.5 °

A: Dear student I have given answer to your question in the image format.

Q: if 11.2 g of H2 (g) (MM = 2.016 g/mol) were to react according to the balanced equation given below,…

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Q: A calorimeter holds 50 g water at 29.0°C. A sample of hot iron is added to the water, and the final…

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Q: A 45.90 g sample of pure copper is heated in a test tube to 99.40°C. The copper sample is then…

A: The amount of heat transferred in a thermodynamic system is calculated as follows,…

Q: What is the specific heat of a metal with a mass of 14g,heat of 3.45kj and a change in temperature…

A: Heat transfer done during this process,q = mCpΔT Given that,heat, q = 3.45 kJ = 3.45x103 J  mass of…