A 350-liter tank initial contains 50 liters of water containing 1 kilogram of salt. Suppose that water containing 0.5 kilograms of salt per liter flows into the top of the tank at a rate of 6 liters per minute. The tank is kept well mixed, and 3 liters per minute is removed from the bottom of the tank. How much salt is in the tank when the tank is full? Round your answer to the nearest tenth of a kilogram. Use x(t) for the amount of salt (in kilograms) in the tank after t minutes, and use V for the volume of solution (in liters) in the tank at time t. You may assume that 0≤t ≤ 100 minutes. You may also assume that the volume of solution in the tank at time t is V = 3t+ 50.
A 350-liter tank initial contains 50 liters of water containing 1 kilogram of salt. Suppose that water containing 0.5 kilograms of salt per liter flows into the top of the tank at a rate of 6 liters per minute. The tank is kept well mixed, and 3 liters per minute is removed from the bottom of the tank. How much salt is in the tank when the tank is full? Round your answer to the nearest tenth of a kilogram. Use x(t) for the amount of salt (in kilograms) in the tank after t minutes, and use V for the volume of solution (in liters) in the tank at time t. You may assume that 0≤t ≤ 100 minutes. You may also assume that the volume of solution in the tank at time t is V = 3t+ 50.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A 350-liter tank initial contains 50 liters of water containing 1 kilogram of
salt. Suppose that water containing 0.5 kilograms of salt per liter flows into the top of the
tank at a rate of 6 liters per minute. The tank is kept well mixed, and 3 liters per minute is
removed from the bottom of the tank. How much salt is in the tank when the tank is full?
Round your answer to the nearest tenth of a kilogram.
Use x(t) for the amount of salt (in kilograms) in the tank after t minutes, and use V for the
volume of solution (in liters) in the tank at time t. You may assume that 0≤t ≤ 100
minutes. You may also assume that the volume of solution in the tank at time t is V = 3t+
50.
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