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A 35.0 mL sample of 0.0200 M Cu2+ buffered at pH 8.00 is titrated with 0.0100 M EDTA. Calculate pCu²+ at each of the added volumes of EDTA. For the Cu2+-EDTA complex, log Kr is 18.78. The fraction of free EDTA in the Y" form, ay4-, can be found in this table. 0 mL pCu2+ = 23.3 mL pCu2+ %3D 70.0 mL pCu2+ = %3D 75.0 mL pCu2+ %3D

A 35.0 mL sample of 0.0200 M Cu2+ buffered at pH 8.00 is titrated with 0.0100 M EDTA. Calculate pCu²+ at each of the added volumes of EDTA. For the Cu2+-EDTA complex, log Kr is 18.78. The fraction of free EDTA in the Y" form, ay4-, can be found in this table. 0 mL pCu2+ = 23.3 mL pCu2+ %3D 70.0 mL pCu2+ = %3D 75.0 mL pCu2+ %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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on 8 of A 35.0 mL sample of 0.0200M Cu2+ buffered at pH 8.00 is titrated with 0.0100 M EDTA. Calculate pCu²+ at each of the added volumes of EDTA. For the Cu²+–EDTA complex, log Kf is 18.78. The fraction of free EDTA in the Y- form, ay4- , can be found in this table. 0 mL pCu2+ %D 23.3 mL pCu?+ : 70.0 mL pCu²+ %3D 75.0 mL pCu?+ =
Transcribed Image Text:on 8 of A 35.0 mL sample of 0.0200M Cu2+ buffered at pH 8.00 is titrated with 0.0100 M EDTA. Calculate pCu²+ at each of the added volumes of EDTA. For the Cu²+–EDTA complex, log Kf is 18.78. The fraction of free EDTA in the Y- form, ay4- , can be found in this table. 0 mL pCu2+ %D 23.3 mL pCu?+ : 70.0 mL pCu²+ %3D 75.0 mL pCu?+ =
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