A 35° 1. A force is applied to the control rod AO as shown. Knowing that the length of the rod is 350 mm, compute the moment of the force about point O using a. Vector method: M, =r x F. b. Scalar method: M, = Fd 150 N 70°
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- Needs Complete typed solution with 100 % accuracy.In the figure, a small 0.289 kg block slides down a frictionless surface through heighth - 0.523 m and then sticks to a uniform vertical rod of mass M-0.578 kg and length d - 2.61 m. The rod pivots about point O through angle before momentarily stopping. Find 9. ARefer to the question below.
- Two forces act on the rod. Determine the resultant moment they create about the flange at O. Express the result as a Cartesian vector. F, = (-60i + 40j + 20k] kN 2 m 4 m B -5 m- F = {80i + 40j- 30k} kNW; = 0 %3D Wf initial final A flywheel consists of a thin uniform disk of mass m and radius R, free to rotate about a frictionless central axle. A small weight, also of mass m, is attached to the wheel's rim. The is wheel is held at rest (left), the small weight level with the axle, then released. What is the angular velocity of the wheel when the weight reaches its lowest point? 4g V 3R 8g V 5R 3g V 2R V28R 2gRCompute the combined moment of the two 80-lb forces about (a) point O and (b) point A. The moment is positive if counterclockwise, negative if clockwise. Assume a = 5.0 in., b=2.7 in., F-80 lb. y 1 F Answers: (a) Mo i (b) MA-i Ib-in. lb-in.
- W L A rod of length L = 35.0 cm rotates about its end through O with a constant angular acceleration a = 2.23 rad/s², as shown in the figure. At t= 0, the initial tangential speed of a point P on the rod is to 14.4 m/s. Find the final tangential speed v of the point P at t = 5 s. O 21.96 O 18.30 O 27.45 O 15.25 12.20Please help showing how to solve this question. According to Canvas, the answer should be 1.367 m/s.The body in the figure is pivoted at O. Three forces act on it in the directions shown: FA = 9.30 N at point A, 5.40 m from O; FB = 13.0N at point B, 2.90 m from O; and Fc = 18.0 N at point C, 2.90 m from O. Taking the clockwise direction to be negative, what is the net %3D torque about O? 135° A C 160° 90 FA Units Number i
- A long, thin uniform rod of length 1.29m and mass 2.08kg is pivoted about a horizontal, frictionless pin passing through one end. The rod is released from one end in the vertical position. L y Pivot x At the instant the rod is horizontal, find its angular speed. Submit Answer Tries 0/10 At the instant the rod is horizontal, what is its angluar acceleration? Submit Answer Tries 0/10 At the instant the rod is horizontal, what is the magnitude of its x-component of acceleration at its centre of mass? Submit Answer Tries 0/10 At the instant the rod is horizontal, what is the magnitude of its Y-component of acceleration at its centre of mass? Submit Answer Tries 0/10A circular disk has a rotational inertia of 9.1 kg.m² and a constant angular acceleration of 8.1 rad/s2. If it starts from rest the work done during the first 2.7 s by the net torque acting on it is: Select one: a. 2176.25 ] Ob.8705.00 1 C. 4352.50 k] d. 4352.50 ]A 50 g solid sphere is rolling without slipping along a horizontal surface at a speed of 800 cm/s. It comes to a point where the surface rises 30 ̊above the horizontal. Neglect energy losses due to friction. a. What is the total energy of the rolling sphere? b. To what vertical height will it roll up the plane?