A 30mm ID, 50mm OD aluminum round tube passes air through it at a rate of 0.08 m^3/s. A 100W electric heater blanket covers the outside of the 2m long tube. If the air enters the tube at 100 celsius , what temperature does it exit at? Assume that the heater blanket is perfectly insulated on the back side (no heat loss out the back). Note-RT is 25 celsius Boundary ConditionLaminar or TurbulentNusselt EquationUniform TemperatureLaminarNu = 0.664Ref5pNu = 0.037Ref"pNu = 0.453R€25P;/3Uniform TemperatureTurbulentUniform Heat FluxLaminarUniform Heat FluxTurbulentNu = 0.038 Rep/3Reynold's Number Ranges:Re <1x 105 - LaminarRe 23 x 106 - Turbulentselt Correlations for Forced Convection over circular and non-circular cylinders in cross-flow.ShapeFluidRange of ReNusselt NumberCylinderGas or Liquid0.4-4Nu = 0.989 Re"p4-40Nu = 0.911 Resp740-4,000Nu = 0.9683 Re 46p4,000 - 40,000Nu = 0.193 Re4p40,000 - 400,000Nu = 0.027Rees pT DensitykgMaterialSpecificLatent Heat Latent HeatThermalof Fusion,ofConductivityHeatkgKAVaporizationW\mK.kg.Air1.2257180.025Aluminum2712900396000200Ammonia68244001371000(Liquid)Cast Iron730046024700040Copper8940390206000400Ероху120010001.5G1018006700.3FiberglassGlass22007501Silicone107013000.2Steel785045024700020

Answered: Image /qna-images/answer/e6e1a231-53f8-446e-9e85-0c5b036b4fe4.jpg

Answered: A 30mm ID, 50mm OD aluminum round tube…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

A 30mm ID, 50mm OD aluminum round tube passes air through it at a rate of 0.08 m^3/s. A 100W electric heater blanket covers the outside of the 2m long tube. If the air enters the tube at 100 celsius , what temperature does it exit at? Assume that the heater blanket is perfectly insulated on the back side (no heat loss out the back).

Note-RT is 25 celsius

Boundary Condition
Laminar or Turbulent
Nusselt Equation
Uniform Temperature
Laminar
Nu = 0.664Ref5p
Nu = 0.037Ref"p
Nu = 0.453R€25P;/3
Uniform Temperature
Turbulent
Uniform Heat Flux
Laminar
Uniform Heat Flux
Turbulent
Nu = 0.038 Rep/3
Reynold's Number Ranges:
Re <1x 105 - Laminar
Re 23 x 106 - Turbulent
selt Correlations for Forced Convection over circular and non-circular cylinders in cross-flow.
Shape
Fluid
Range of Re
Nusselt Number
Cylinder
Gas or Liquid
0.4-4
Nu = 0.989 Re"p
4-40
Nu = 0.911 Resp7
40-4,000
Nu = 0.9683 Re 46p
4,000 - 40,000
Nu = 0.193 Re4p
40,000 - 400,000
Nu = 0.027Rees pT

Density
kg
Material
Specific
Latent Heat Latent Heat
Thermal
of Fusion,
of
Conductivity
Heat
kgKA
Vaporization
W
\mK.
kg.
Air
1.225
718
0.025
Aluminum
2712
900
396000
200
Ammonia
682
4400
1371000
(Liquid)
Cast Iron
7300
460
247000
40
Copper
8940
390
206000
400
Ероху
1200
1000
1.5
G10
1800
670
0.3
Fiberglass
Glass
2200
750
1
Silicone
1070
1300
0.2
Steel
7850
450
247000
20

Expert Solution

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions