A 3000-lb car is parked on a 30° slope, facing uphill. The center of mass of the car is halfway between the front and rear wheels and is 2 ft above the ground. The wheels are 8 ft apart. Find the normal force exerted by the road on the front wheels and on the rear wheels. I le 0 = 30° 4 = 2 ft ½ = 4 ft mg
A 3000-lb car is parked on a 30° slope, facing uphill. The center of mass of the car is halfway between the front and rear wheels and is 2 ft above the ground. The wheels are 8 ft apart. Find the normal force exerted by the road on the front wheels and on the rear wheels. I le 0 = 30° 4 = 2 ft ½ = 4 ft mg
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Transcribed Image Text:A 3000-lb car is parked on a 30° slope, facing uphill. The center of mass of the car is halfway between the front
and rear wheels and is 2 ft above the ground. The wheels are 8 ft apart. Find the normal force exerted by the road
on the front wheels and on the rear wheels.
0 = 30°
l = 2 ft
2 = 4 ft
mg
Hints :
The car is in stationary equilibrium, so :
1) the total force on the car must be 0 (i.e., along the incline and perpendicular to it),
2) the total torque about any point must be 0. (choose as point of rotation the center of mass)
Remember friction is: f = µ N
Three equations , three unknowns. Solve for N1 and N2.
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