A 30 nC charge experiences a 0.023 N electric force. ▼ Part A What is the magnitude of electric field at the position of this charge? Express your answer with the appropriate units.
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- I don't understand why this is the correct graph, particularly why the electric field strength is negative between the charges. Can you please explain?A +4.2×10-⁹ C charged object is 6.9 cm along a horizontal line toward the right of a -3.3×10-9 C charged object. Part A Determine the E field at a point 4.0 cm to the left of the negative charge.What is the acceleration of the a particle?
- Suppose that a wire leads into another, thinner wire of the same material that has only half the cross-sectional area. In the steady state, the number of electrons per second flowing through the thick wire must be equal to the number of electrons per second flowing through the thin wire. If the electric field Ej in the thick wire is 4.3 x 102 N/C, what is the electric field E2 in the thinner wire? i N/CElectric Fields 12 v.C What is the direction of the electric field E2? Enter the numerical value in units of y degrees above the +x axis. E2 Type your answer... E2y 13 If electric field E1 has a magnitude of E1 = 3.7 N/C, what is the magnitude of the total (or net) electric field? Enter the numerical value in SI units. E1 E2x Type your answer.. Two electric fields (E1 and E2) occupy the same point in empty space, as shown above. Electric field E2 has a magnitude of E2 = 5.0 N/C, an x-component of E2x = 3.0 N/C, and a y-component of E2y = 4.0 N/C. %3D %3DPart A The permanent electric dipole moment of the water molecule (H2 0) is 6.2 × 10-30 C.m. What is the maximum possible torque on a water molecule in a 4.0x108 N/C electric field? Express your answer in newton-meters. nνα ΑΣφ Vx X•10n b. N m Submit Previous Answers Request Answer
- A3Point charge A is on the x-axis at z = -3.00 cm. At x = 1.00 cm on the x-axis its electric field is 2700 N/C. Point charge B is also on the x-axis, at a = 5.00 cm. The absolute magnitude of charge B is twice that of A. Part A Find the magnitude and direction of the total electric field at the origin if both A and B are positive. Express your answer in newtons per coulomb. Enter positive value if the field points in +x-direction and negative value if the field points in -x-direction. Ez = N/C Part B Find the magnitude and direction of the total electric field at the origin if both A and B are negative. Express your answer in newtons per coulomb. Enter positive value if the field points in +x-direction and negative value if the field points in -x-direction. E = N/CA uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate, 1.60 cm distant from the first, in a time interval of 1.50 × 10-6 s. a. Find the magnitude of the electric field. b. Find the speed of the proton when it strikes the negatively charged plate. Hint: Use both kinematics and electric field equations in solving the problem
- A downward electric force of 3.6N is exerted on a −7.6μC charge. A. Find the magnitude of the electric field at the position of this charge. Express your answer to two significant figures and include the appropriate units. B. What is the direction of the electric field at the position of this charge? Downward or upward?Q1Two 10-cm-diameter charged rings face each other, 25.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength: Part A For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Charge on a Van De Graaff. at the midpoint between the two rings? Express your answer with the appropriate units. HÀ ? Value Units Submit Request Answer Part B at the center of the left ring? Express your answer with the appropriate units.