A 30 mm diameter shaft rotates in a 30.1 mm inner diameter and 60 mm long bearing with a frequency of 5000 rpm. At that frequency it can be assumed that the eccentricity is zero. The lubricant used is SAE-30 oil at 60 ° C (μ = 4 x 10-2 Nm-2s). What is the power absorbed by the mechanism? Remember that W = C. ω, Where: ω = angular velocity = 2πf, C = conjugate (moment or torque) and 1hp = 736W = 75 kg.m/s. Expected Answer: w = 0.38hp
A 30 mm diameter shaft rotates in a 30.1 mm inner diameter and 60 mm long bearing with a frequency of 5000 rpm. At that frequency it can be assumed that the eccentricity is zero. The lubricant used is SAE-30 oil at 60 ° C (μ = 4 x 10-2 Nm-2s). What is the power absorbed by the mechanism? Remember that W = C. ω, Where: ω = angular velocity = 2πf, C = conjugate (moment or torque) and 1hp = 736W = 75 kg.m/s. Expected Answer: w = 0.38hp
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A 30 mm diameter shaft rotates in a 30.1 mm inner diameter and 60 mm long bearing with a frequency of 5000 rpm. At that frequency it can be assumed that the eccentricity is zero. The lubricant used is SAE-30 oil at 60 ° C (μ = 4 x 10-2 Nm-2s). What is the power absorbed by the
ω = angular velocity = 2πf, C = conjugate (moment or torque) and 1hp = 736W = 75 kg.m/s.
Expected Answer: w = 0.38hp
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