A 3.0 m long wire carrying a current of 1.0 A through a magnetic field of magnitude 17.0 T experiences a force of 8.0 N entirely due to the current passing through the magnetic field. What angle does the wire make with the magnetic field?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A 3.0 m long wire carrying a current of 1.0 A through a magnetic field of magnitude 17.0 T experiences a force of 8.0 N entirely due to the current passing through the magnetic field. What angle does the wire make with the magnetic field? 

**Explanation:**

To find the angle, you can use the formula for the magnetic force on a current-carrying wire:

\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]

Where:
- \( F \) is the force (8.0 N)
- \( I \) is the current (1.0 A)
- \( L \) is the length of the wire (3.0 m)
- \( B \) is the magnetic field strength (17.0 T)
- \( \theta \) is the angle between the wire and the magnetic field

The task is to solve for \( \theta \).
Transcribed Image Text:**Problem Statement:** A 3.0 m long wire carrying a current of 1.0 A through a magnetic field of magnitude 17.0 T experiences a force of 8.0 N entirely due to the current passing through the magnetic field. What angle does the wire make with the magnetic field? **Explanation:** To find the angle, you can use the formula for the magnetic force on a current-carrying wire: \[ F = I \cdot L \cdot B \cdot \sin(\theta) \] Where: - \( F \) is the force (8.0 N) - \( I \) is the current (1.0 A) - \( L \) is the length of the wire (3.0 m) - \( B \) is the magnetic field strength (17.0 T) - \( \theta \) is the angle between the wire and the magnetic field The task is to solve for \( \theta \).
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