### Problem DescriptionA 3.0-kg block (A) is attached to a 1.0-kg block (B) by a massless spring that is compressed and locked in place, as illustrated in the figure. The blocks slide without friction along the x-direction at an initial constant speed of \( v = 2.0 \, \text{m/s} \).At time \( t_0 = 0 \, \text{s} \), the positions of blocks A and B are \( x_{A,i} = 1.0 \, \text{m} \) and \( x_{B,i} = 1.2 \, \text{m} \), respectively. At this point, a mechanism releases the spring, causing the blocks to begin oscillating as they slide.---### Figure ExplanationThe diagram consists of two configurations:1. **Initial Configuration:** - Block A and Block B are aligned horizontally with Block A on the left and Block B on the right. - The spring between them is compressed. - An initial velocity vector (\( \vec{v} \)) indicates the direction of motion towards the right.2. **Final Configuration:** - The blocks are now spaced apart with the spring extended. - Their final positions are indicated as \( x_{A,f} \) for Block A and \( x_{B,f} \) for Block B. - The movement direction remains towards the right, marked by the x-axis.---### QuestionIf 2.0 seconds later, block B is located at \( x_{B,f} = 7.5 \, \text{m} \), what will be the position \( x_{A,f} \) of block A?\[x_{A,f} = \, \phantom{e} \text{m}\]

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A 3.0-kg block (A) is attached to a 1.0-kg block (B) by a massless spring that is compressed and locked in place, as shown in the figure. The blocks slide without friction along A A 000B the x-direction at an initial constant speed of v = 2.0 m/s. At time to = 0 s, the positions of blocks A and B are XAi = 1.0 m and xBi = 1.2 m, respectively, at which point a XB.i XB.f mechanism releases the spring, and the blocks begin to oscillate as they slide. If 2.0 s later block B is located at xBf = 7.5 m, what will be the position xAf of block A? XA.f = m

A 3.0-kg block (A) is attached to a 1.0-kg block (B) by a massless spring that is compressed and locked in place, as shown in the figure. The blocks slide without friction along A A 000B the x-direction at an initial constant speed of v = 2.0 m/s. At time to = 0 s, the positions of blocks A and B are XAi = 1.0 m and xBi = 1.2 m, respectively, at which point a XB.i XB.f mechanism releases the spring, and the blocks begin to oscillate as they slide. If 2.0 s later block B is located at xBf = 7.5 m, what will be the position xAf of block A? XA.f = m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

### Problem Description

A 3.0-kg block (A) is attached to a 1.0-kg block (B) by a massless spring that is compressed and locked in place, as illustrated in the figure. The blocks slide without friction along the x-direction at an initial constant speed of \( v = 2.0 \, \text{m/s} \).

At time \( t_0 = 0 \, \text{s} \), the positions of blocks A and B are \( x_{A,i} = 1.0 \, \text{m} \) and \( x_{B,i} = 1.2 \, \text{m} \), respectively. At this point, a mechanism releases the spring, causing the blocks to begin oscillating as they slide.

---

### Figure Explanation

The diagram consists of two configurations:

1. **Initial Configuration:**
- Block A and Block B are aligned horizontally with Block A on the left and Block B on the right.
- The spring between them is compressed.
- An initial velocity vector (\( \vec{v} \)) indicates the direction of motion towards the right.

2. **Final Configuration:**
- The blocks are now spaced apart with the spring extended.
- Their final positions are indicated as \( x_{A,f} \) for Block A and \( x_{B,f} \) for Block B.
- The movement direction remains towards the right, marked by the x-axis.

---

### Question

If 2.0 seconds later, block B is located at \( x_{B,f} = 7.5 \, \text{m} \), what will be the position \( x_{A,f} \) of block A?

\[
x_{A,f} = \, \phantom{e} \text{m}
\]

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