A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at B, 50 A at 0-707 p.f lagging at C and 30 A at 0-8 p.f lagging at D, the load curents being referred to the supply voltage at A. The impedances per phase of the various sections are : Section AB = (1 +j 2)2 Section BC = (2 +j 3) 2 Section DA = (3 +j 4) 2 Section CD = (1+j 1)2 Calculate the currents in various sections and station bus-bar voltages at B, C and D. [Current in AB = (53-8 -j 46) amp ; BC = (21-8 -j 22) amp. CD = (-13-55 +j 13-35) amp ; DA = (-40-55 - j 26-45) amp. Vg = (6212-5 -j 61-6) volts/phase ; Vc= (6103 - j 83) volts/phase V2= (6129-8 - j 82-8) volts/phase]
A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at B, 50 A at 0-707 p.f lagging at C and 30 A at 0-8 p.f lagging at D, the load curents being referred to the supply voltage at A. The impedances per phase of the various sections are : Section AB = (1 +j 2)2 Section BC = (2 +j 3) 2 Section DA = (3 +j 4) 2 Section CD = (1+j 1)2 Calculate the currents in various sections and station bus-bar voltages at B, C and D. [Current in AB = (53-8 -j 46) amp ; BC = (21-8 -j 22) amp. CD = (-13-55 +j 13-35) amp ; DA = (-40-55 - j 26-45) amp. Vg = (6212-5 -j 61-6) volts/phase ; Vc= (6103 - j 83) volts/phase V2= (6129-8 - j 82-8) volts/phase]
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at
B, 50 A at 0-707 p.f lagging at C and 30 A at 0-8 p.f lagging at D, the load curents being referred to the
supply voltage at A.
The impedances per phase of the various sections are :
Section AB = (1 +j 2)2
Section BC = (2 +j 3)2
Section DA = (3 +j 4) 2
Section CD = (1+j 1)2
Calculate the currents in various sections and station bus-bar voltages at B, C and D.
[Current in AB = (53-8 -j 46) amp ; BC = (21-8 –j 22) amp.
CD = (-13-55 +j 13-35) amp ; DA = (40-55 -j 26-45) amp.
V3 = (6212-5 -j 61-6) volts/phase ; Vc= (6103 – j 83) volts/phase
V2= (6129-8 – j 82-8) volts/phase]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ef45011-125d-4c4f-bf90-84b26ce3075d%2Fb73474ae-a359-41e7-b84e-eb3917d1cce6%2Frskw4ah_processed.png&w=3840&q=75)
Transcribed Image Text:A 3-phase ring distributor ABCD fed at A at 11 kV supplies balanced loads of 40 A at 0-8 p.f. lagging at
B, 50 A at 0-707 p.f lagging at C and 30 A at 0-8 p.f lagging at D, the load curents being referred to the
supply voltage at A.
The impedances per phase of the various sections are :
Section AB = (1 +j 2)2
Section BC = (2 +j 3)2
Section DA = (3 +j 4) 2
Section CD = (1+j 1)2
Calculate the currents in various sections and station bus-bar voltages at B, C and D.
[Current in AB = (53-8 -j 46) amp ; BC = (21-8 –j 22) amp.
CD = (-13-55 +j 13-35) amp ; DA = (40-55 -j 26-45) amp.
V3 = (6212-5 -j 61-6) volts/phase ; Vc= (6103 – j 83) volts/phase
V2= (6129-8 – j 82-8) volts/phase]
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