A 3 bit binand counter is implemented as a state machine that produce consecutive output at each vising clock. C A BN 1600. AN CN CLK 0 0 1 DOLCHONS 1 1 D PC1 1 1 0 them repeating 1 1 O O The crossesponding circuit is shown below 1 O 19 #CL O O 10 >C1 0 जनत 1 1 ? A B с
A 3 bit binand counter is implemented as a state machine that produce consecutive output at each vising clock. C A BN 1600. AN CN CLK 0 0 1 DOLCHONS 1 1 D PC1 1 1 0 them repeating 1 1 O O The crossesponding circuit is shown below 1 O 19 #CL O O 10 >C1 0 जनत 1 1 ? A B с
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Transcribed Image Text:The values of the output are represented as
A, B, C and their value at next state as
Ani Bnicn
(a) what is the boolean expression of An?
(i) An= A (B-C) (ui) AN=C (iii) AN=A (@D(B+C)
(iv) AN= A + C
(V) AN=A&D (B+C) (V1) AN=BOC
(VII) AN=AB (VIII) AN= AÐB
(¹X) AN=B
(X11) AN=Ã
(X) AN = A B (B.C) (X1) AN=B&C
(16) what is the expression of BN?
(1) BN=C
UBNFA Đ(BTC) lui) BN B
(IV) BN: (BBC) (V) BN-(ABC) (VI) BN=A
(VII) BN=AB (VIII) BN=AB(BC) | 1x) BN = AÐ (B.C)
(X) BN=A (B+C) (X1) BN= BOC (XII) BN=A@B
(c) what is Boolean expression of Cn?
(1) CN=B
(11) CN=AOC (111) CN=C
(IV) (N=BOC (V) CN=A
(VIDGFA ĐIBIO)
(VII) (N=ALB·C) (VIII) (N = AⒸ (B+C) (IX) (N=(AB) C
(X) (N = AⓇB (XI) CN = AⒸB (XII) CN=BOC
Transcribed Image Text:A 3 bit binary counter is implemented as a
state machine that produce consecutive output
lateach vising clock.
A
00.
BN
1
AN
CN
CLK
1
PHOTO
0
1 D
"CI
19
1
1
0
0
1
then repeating
1
O
The crossesponding circuit is shown belowe
1
0
1
O
C1
O
10
DC1
O
O
1
ततन
1
1
1
?
A
B
с
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