A 2nd Harmonic standing wave with amplitude of 5 mm exists on a 0.8 m long string that is fixed at both ends. The wave velocity for this string is 200 m/s. Using the wave function for a standing wave, y(x,t) = A sin(kx) sin(ot), calculate the local vibration amplitude at x = 0.15 m, when t = 5.5 msec.
A 2nd Harmonic standing wave with amplitude of 5 mm exists on a 0.8 m long string that is fixed at both ends. The wave velocity for this string is 200 m/s. Using the wave function for a standing wave, y(x,t) = A sin(kx) sin(ot), calculate the local vibration amplitude at x = 0.15 m, when t = 5.5 msec.
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![A 2nd Harmonic standing wave with amplitude of 5 mm exists on a 0.8 m long string that is fixed at both
ends. The wave velocity for this string is 200 m/s. Using the wave function for a standing wave, y(x,t) =
A sin(kx) sin(ot), calculate the local vibration amplitude at x = 0.15 m, when t = 5.5 msec.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae2b6eb5-0b25-4f0e-97e4-54bb25b6155d%2F72d9d01b-f498-4455-8b41-31782eace82f%2Fv0lr7e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 2nd Harmonic standing wave with amplitude of 5 mm exists on a 0.8 m long string that is fixed at both
ends. The wave velocity for this string is 200 m/s. Using the wave function for a standing wave, y(x,t) =
A sin(kx) sin(ot), calculate the local vibration amplitude at x = 0.15 m, when t = 5.5 msec.
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