A + 2B + 20 → 3D + 3E Experiment [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.35 0.35 0.35 8.0 x10-4 2 0.70 0.35 0.35 3.2 x10-3 3 0.70 0.70 0.35 6.4 x10-3 4 0.70 0.35 0.70 3.2 x10-3 R=k[A]2 [B]1 [C]1 R=k[A]1 [B]2 [C]0 R=k[A]2 [B]1 [C]0 R=k[A]1 [B]2 [C]2
A + 2B + 20 → 3D + 3E Experiment [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.35 0.35 0.35 8.0 x10-4 2 0.70 0.35 0.35 3.2 x10-3 3 0.70 0.70 0.35 6.4 x10-3 4 0.70 0.35 0.70 3.2 x10-3 R=k[A]2 [B]1 [C]1 R=k[A]1 [B]2 [C]0 R=k[A]2 [B]1 [C]0 R=k[A]1 [B]2 [C]2
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![A+ 2B + 20 -→ 3D + 3E
Experiment [A] (M)
[B] (M)
[C] (M)
Initial rate (M/s)
1
0.35
0.35
0.35
8.0 x104
2
0.70
0.35
0.35
3.2 x10-3
3
0.70
0.70
0.35
6.4 x10-3
4
0.70
0.35
0.70
3.2 x10-3
R=k[A]2 [B]1 [C]1
R=k[A]1 [B]2 [C]O
R=k[A]2 [B]1 [C]o
O R=k[A]1 [B]2 [C]2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86158032-ed7c-43a3-b5cc-df6a415b87b0%2Fcad25c50-e84f-46e9-837d-c141bd8aa3f9%2Fm28av9f_processed.png&w=3840&q=75)
Transcribed Image Text:A+ 2B + 20 -→ 3D + 3E
Experiment [A] (M)
[B] (M)
[C] (M)
Initial rate (M/s)
1
0.35
0.35
0.35
8.0 x104
2
0.70
0.35
0.35
3.2 x10-3
3
0.70
0.70
0.35
6.4 x10-3
4
0.70
0.35
0.70
3.2 x10-3
R=k[A]2 [B]1 [C]1
R=k[A]1 [B]2 [C]O
R=k[A]2 [B]1 [C]o
O R=k[A]1 [B]2 [C]2
![9
Using the data given below, determine the rate law expression for the following
reaction. .](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86158032-ed7c-43a3-b5cc-df6a415b87b0%2Fcad25c50-e84f-46e9-837d-c141bd8aa3f9%2Fnd329ll_processed.png&w=3840&q=75)
Transcribed Image Text:9
Using the data given below, determine the rate law expression for the following
reaction. .
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