A 28.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 55.0N is required to keep the block moving with constant speed. (a) Find the coefficient of static friction between the block and the surface. (b) Find the coefficient of kinetic friction between the block and the surface.
A 28.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 55.0N is required to keep the block moving with constant speed. (a) Find the coefficient of static friction between the block and the surface. (b) Find the coefficient of kinetic friction between the block and the surface.
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![### Physics Problem: Calculating Friction Coefficients
**Problem Statement:**
A 28.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 55.0 N is required to keep the block moving with constant speed.
**Tasks:**
(a) Find the coefficient of static friction between the block and the surface.
(b) Find the coefficient of kinetic friction between the block and the surface.
**Solution Steps:**
(a) Find the coefficient of static friction between the block and the surface.
- [Input Box for Answer]
(b) Find the coefficient of kinetic friction between the block and the surface.
- [Input Box for Answer]
**Explanation:**
For part (a), we need to determine the coefficient of static friction (\(\mu_s\)). The force required to start the motion (F_static) is 79.0 N. The normal force (N), which is equal to the weight of the block (mass * gravity), can be calculated as follows:
\[ N = m \cdot g \]
\[ N = 28.0 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \]
The coefficient of static friction is given by:
\[ \mu_s = \frac{F_{\text{static}}}{N} \]
For part (b), we need to find the coefficient of kinetic friction (\(\mu_k\)). The force required to keep the block moving at a constant speed (F_kinetic) is 55.0 N. The normal force (N) is the same as calculated above.
The coefficient of kinetic friction is given by:
\[ \mu_k = \frac{F_{\text{kinetic}}}{N} \]
*[Note to students: Be sure to input your final answers in the provided input boxes.]*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb82cdd93-87a8-4004-913f-cae9a7e1e525%2F70f4a52a-7497-42a0-a8a3-0a1ea1836eed%2F1nttsqo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Calculating Friction Coefficients
**Problem Statement:**
A 28.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 55.0 N is required to keep the block moving with constant speed.
**Tasks:**
(a) Find the coefficient of static friction between the block and the surface.
(b) Find the coefficient of kinetic friction between the block and the surface.
**Solution Steps:**
(a) Find the coefficient of static friction between the block and the surface.
- [Input Box for Answer]
(b) Find the coefficient of kinetic friction between the block and the surface.
- [Input Box for Answer]
**Explanation:**
For part (a), we need to determine the coefficient of static friction (\(\mu_s\)). The force required to start the motion (F_static) is 79.0 N. The normal force (N), which is equal to the weight of the block (mass * gravity), can be calculated as follows:
\[ N = m \cdot g \]
\[ N = 28.0 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \]
The coefficient of static friction is given by:
\[ \mu_s = \frac{F_{\text{static}}}{N} \]
For part (b), we need to find the coefficient of kinetic friction (\(\mu_k\)). The force required to keep the block moving at a constant speed (F_kinetic) is 55.0 N. The normal force (N) is the same as calculated above.
The coefficient of kinetic friction is given by:
\[ \mu_k = \frac{F_{\text{kinetic}}}{N} \]
*[Note to students: Be sure to input your final answers in the provided input boxes.]*
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