**Physics Problem Explanation: Trampoline Kinetic Energy****Problem Statement:**A 28-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. How high does she rise during this interval? Neglect air resistance.**Solution:**To solve this problem, we can use the principle of conservation of energy. The loss in kinetic energy will equal the gain in potential energy as she rises.1. Initial kinetic energy (\(KE_i\)) = 420 J2. Final kinetic energy (\(KE_f\)) = 220 J**Step 1: Calculate the change in kinetic energy:**\[\Delta KE = KE_i - KE_f\]\[\Delta KE = 420 \text{ J} - 220 \text{ J} = 200 \text{ J}\]**Step 2: Relate this change to potential energy:**The change in kinetic energy will be equal to the change in potential energy since air resistance is neglected:\[\Delta KE = \Delta PE\]**Step 3: Use the potential energy formula:**Potential energy (\(PE\)) gained by the girl as she rises:\[PE = mgh\]Where:- \(m\) is the mass (28 kg)- \(g\) is the acceleration due to gravity (9.8 m/s²)- \(h\) is the height she rises**Step 4: Solve for height (\(h\)):**\[200 \text{ J} = (28 \text{ kg})(9.8 \text{ m/s}^2)(h)\]\[200 \text{ J} = 274.4 \text{ kg} \cdot \text{m/s}^2 \cdot h\]\[h = \frac{200 \text{ J}}{274.4 \text{ kg} \cdot \text{m/s}^2}\]\[h \approx 0.73 \text{ m}\]**Conclusion:**The girl rises approximately 0.73 meters during this interval when her kinetic energy decreases from 420 J to 220 J.

Answered: Image /qna-images/answer/dc8c8a84-db6b-4bc2-8e47-1d511bc992ea.jpg

A 28-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. How high does she rise during this interval? Neglect air resistance.

A 28-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. How high does she rise during this interval? Neglect air resistance.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A 2 kg block, initially at rest, is pulled horizontally with a cable with a tension of 1O N. The surface has a kinetic coefficient of friction of 0.3. How long does it take for the block to travel 1.75 m? Give your answer in seconds.
A 5-kg bag is gently pushed off the top of a wall and swings in a vertical plane at the end of a 2.4- m rope which can withstand a maximum tension Fm. For Fm from 40 to 140 N use computational software to determine (a) the difference in elevation h between point A and point B where the rope will break, (b) the distance d from the vertical wall to the point where the bag will strike the floor. -2.4m A 3m B'
A rubber ball (4 kg) falls from a height of 50 m and collides elastically with the floor. What is the velocity of the ball just after it rebounds from the floor?
A body of mass 10 kg is initially stationary on a 45 degree inclined plane , coefficient of friction is 0.5. The body slides down the plate and attains a velocity of 20 m/s. Find out distance travel by the body along the plane.
A simple pendulum consists of a 0.8- kg bob connected to a massless inextensible cord with a length L = 1.9 m. The bob is set into motion and its angular displacement is given by e(t) = 0.11cos(wt), where e is in radians and t is in seconds. Take g = 9.8 m/s^2, determine the mechanical energy of this pendulum.
20. Two objects are connected to each other by a rope over a pulley as in the figure. The 8.00 kg and mp = 11.0 kg. If initially ma is at rest 1.36 m from the masses are mA= edge of the table, how long does it take to reach the edge of the table if the system is allowed to move freely (i.e. with no friction)? Mg (c) 1.97 s (a) 12.3 s (d) 0.692 s (b) 0.413 s (e) 5.38 s
4
Consider the mass-on-a-spring system as shown in the figure below. The spring has a spring constant of 1.86e+3 N/m, and the block has a mass of 1.39 kg. There is a constant force of kinetic friction between the mass and the floor of 4.71 N. Starting with the spring compressed by 0.117 m from its equilibrium position, how far will the block travel once it leaves the spring? (Assume that block leaves the spring at the spring's equilibrium position, marked x=0 in the figure. Give your answer as the distance from the equilibrium position to the final position of the block.) Hint: How much work must friction do in order to bring the mass to a stop? How much distance is required for friction to do this work? Enter answer here www.m X = 0 Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8 Image size: S M L Max m
A simple pendulum consists of a 0.8-kg bob connected to a massless inextensible cord with a length L = 1.1 m. The bob is set into motion and its angular displacement is given by e(t) = 0.11cos(wt), where e is in radians and t is in seconds. Take g = 9.8 m/s^2, determine the mechanical energy of this pendulum.
Two masses with mass mA = 3.051 kg and mB = 21.09 kg, respectively, hang with a massless rope over a homogeneous pulley with mass mC = 40.4 kg. The mass center of the pulley is located in the middle of the pulley. The pulley is attached with a frictionless bearing in the middle. g = 9,806 m/s². Calculate the upward force with which the line affects mass B if the pulley is a homogeneous circular disc with a radius of 0.444 m.
แสดงวิธีทำให้ดูหน่อยครับ