A 250 mL of 1% m/v Na2CO3 (MW = 105.99 g/mol) w

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Q: Activity 4: FROZEN / Directions: Apply your knowledge of molality to solve the problems below…

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A: Answer: 0.9% (m/v) saline solution suggests that in 100mL solution 0.9g NaCl is present.

Q: 5-7: A 10.34 molal aqueous nitric acid solution was prepared. (Density of nitric acid = 1.51 g/mL,…

A: Hi, since you have posted multiple questions. We will answer very first questions. Kindly repost the…

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A: Formula used molality = no. of moles of solute/ kg of solvent Density = mass/volume

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A: Molality of solution is defined as number of moles of solute dissolved per kilogram of solvent.

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A: Molality of the solution can be determined by dividing the number of moles of solute by the mass of…

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Q: SOLUTE (NONELECTROLYTE) SOLVENT (WATER) Mass (g) MW (g/mol) Density (g/mL) 60 700 200 18 1.5 1.0

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Q: 5-7: A 10.34 molal aqueous nitric acid solution was prepared. (Density of nitric acid = 1.51 g/mL,…

A: Given data: Molality of nitric acid = 10.34 m Density of nitric acid = 1.51 g/ml Density of water =…

Q: A 250 mL of 1% m/v Na2CO3 (MW = 105.99 g/mol) was found to have a density of 1.05 g/mL at 25oC. Find…

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Q: A solution is made using 90.1 g of dimethyl ether (molar mass = 46.07 g/mol) and 110.0 g of methanol…

A: Given  Mass of dimethyl ether = 90.1 g Mass of methanol = 110.0 g

Q: 7. A 1.37 g/cm' solution is made up with two-thirds of its mass from water and the rest with solute…

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A: Depression in freezing point is directly proportional to the molality of the solution. The relation…

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Q: 5-7: A 10.34 molal aqueous nitric acid solution was prepared. (Density of nitric acid = 1.51 g/mL,…

A: Given data: Molality of nitric acid solution = 10.34 m Density of nitric acid = 1.51 g/mL Density of…