A 25.3-mF capacitor is connected in series with a 19.7-mF capacitor. Calculate the equivalent capacitance of the combination (in mF).
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A: Capacitance, C = 2.4 μFNumber of capacitors connected in series is 3.Combined capacitance, Ce = ?
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Let, capacitor
Capacitor
Equivalent capacitance C = ?
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- The figure below shows three capacitors with capacitances CA = 1.00 μF, CB = 1.20 μF, and Cc = 3.30 μF connected to a 6.00-V battery. QB Qc = (a) What is the equivalent capacitance of the three capacitors? UF = CA (b) What charge is stored in each of the capacitors? QA μC HC CB = = Cc UC + (c) What is the potential difference across each of the capacitors? AVA V AVB AVc = VPLS. ANSWER IN COMPLETE SOLUTIONSuppose you have a 9.00 V battery, a 2.8 μF capacitor, and a 8.65 μF capacitor. Part (a) Find the total charge stored in the system if the capacitors are connected to the battery in series in C. Q = Part (b) Find the energy stored in the system if the capacitors are connected to the battery in series in J. Us = 8.59*10^-5 Part (c) Find the charge if the capacitors are connected to the battery in parallel in C. Q = Part (d) Find the energy stored if the capacitors are connected to the battery in parallel in J. Up =
- Q 10 pleaseThe figure below shows three capacitors with capacitances CA = 1.00 µF, CB = 1.60 µF, and CC = 3.80 µF connected to a 6.00-V battery. (a) What is the equivalent capacitance of the three capacitors? µF(b) What charge is stored in each of the capacitors? QA = µC QB = µC QC = µC (c) What is the potential difference across each of the capacitors? ΔVA = V ΔVB = V ΔVC = VA system of capacitors is shown below. What is the equivalent capacitance of the system if the individual capacitors are: Express the answer in microFarads. For example, if the answer came out to be 4.98 x 10-7 F, this is the same as 49.8 microFarads. You would then answer with numeric value of 4.98. C1 = 6.6 x 10-6 F C2 = 5.9 x 10-6 F C3 = 3.4 x 10-6 F C4 = 4.4 x 10-6 F C5 = 8.1 x 10-6 F
- Two (2.80x10^0) µF capacitors are connected in parallel with a (5.0x10^1) V DC power supply. After the capacitors are fully charged, what is the combined electric potential energy stored in the capacitors? Give your answer in joules (J) using scientific notation.Two capacitors provide an equivalent capacitance of 16.00 μμF when connected in parallel and 4.00 μμF when connected in series. 1)What is the smaller capacitance of the capacitors? If both capacitors have the same capacitance, enter this value. (Express your answer to three significant figures.) 2)What is the larger capacitance of the capacitors? If both capacitors have the same capacitance, enter this value. (Express your answer to three significant figures.)If the capacitance of capacitor A is 84.0 μF, the capacitance of capacitor B is 56.0 μF, and the capacitance of capacitor C is 55.0 μF, what is the equivalent capacitance of the three capacitors (in μF)?
- A parrallel plate capacitor consisting of two 30.0 cm x 30.0 cm square conductors are separated by a 3.00 mm piece of mica (k=5.00) is charged by a connecting it to an 18.0 V battery. What is the capacitance of this capacitor? What is the charge on the capacitor? If the mica is removed and replaced with glass (k=7.00), what is the potential difference of the plates now? What is the charge on the capacitor now with the glass?A system of capacitors is shown below. What is the equivalent capacitance of the system is the individual capacitors are; Express the answer in microFarads. For example, if the answer came out to be 4.98 X 10-7 F, this is the same as 49.8 microFarads. You would then answer with the numeric value of 4.98. C1 = 6.7 x 10-6 F C2 = 4.2 x 10-6 F C3 = 2.1 x 10-6 F C4 = 2.6 x 10-6 F C5 = 6.3 x 10-6 FFind the following. (In the figure use C1 = 37.80 µF and C2 = 31.80 µF.) (a) the equivalent capacitance of the capacitors in the figure above µF(b) the charge on each capacitor on the right 37.80 µF capacitor µC on the left 37.80 µF capacitor µC on the 31.80 µF capacitor µC on the 6.00 µF capacitor µC (c) the potential difference across each capacitor on the right 37.80 µF capacitor V on the left 37.80 µF capacitor V on the 31.80 µF capacitor V on the 6.00 µF capacitor V