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A 25.00 ml of 0.04132 M Hg,(NO3), was titrated with 0.05789M KIO, Hg,2+ + 210; -> Hg,(103)2(9) For Hg, (103)2(s), Ksp = 1.3x10-18. Find [Hg,2*] in the solution after addition of (a) 34.00 ml of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point. %3D

A 25.00 ml of 0.04132 M Hg,(NO3), was titrated with 0.05789M KIO, Hg,2+ + 210; -> Hg,(103)2(9) For Hg, (103)2(s), Ksp = 1.3x10-18. Find [Hg,2*] in the solution after addition of (a) 34.00 ml of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point. %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 25.00 ml of 0.04132 M Hg,(NO3), was titrated with 0.05789M KIO, Hg,2+ + 210; -> Hg,(103)2(9) For Hg, (103)2(s), Ksp = 1.3x10-18. Find [Hg,2*] in the solution after addition of (a) 34.00 ml of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point. %3D
Transcribed Image Text:A 25.00 ml of 0.04132 M Hg,(NO3), was titrated with 0.05789M KIO, Hg,2+ + 210; -> Hg,(103)2(9) For Hg, (103)2(s), Ksp = 1.3x10-18. Find [Hg,2*] in the solution after addition of (a) 34.00 ml of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point. %3D
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