A 24.4 mL sample of 0.2124 M hydrotelluric acid, H₂Te, is titrated with 0.2124 M potassium hydroxide. What is the pH after 12.2 mL, 24.4 mL, 36.6 mL and 48.8 mL of KOH have been added? step mL KOH added pH 1 2 3 4 Not submitted 12.2 24.4 36.6 48.8 second ionization constants for H₂Te are 2.3x10-3 and 1.6x10-11
A 24.4 mL sample of 0.2124 M hydrotelluric acid, H₂Te, is titrated with 0.2124 M potassium hydroxide. What is the pH after 12.2 mL, 24.4 mL, 36.6 mL and 48.8 mL of KOH have been added? step mL KOH added pH 1 2 3 4 Not submitted 12.2 24.4 36.6 48.8 second ionization constants for H₂Te are 2.3x10-3 and 1.6x10-11
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 24.4 mL sample of 0.2124 M hydrotelluric acid, H₂Te, is titrated with 0.2124 M potassium
hydroxide.
What is the pH after 12.2 mL, 24.4 mL, 36.6 mL and 48.8 mL of KOH have been added?
step mL KOH added pH
1
12.2
24.4
36.6
48.8
Not submitted
2
3
4
second ionization constants for H₂Te are 2.3x10-3 and 1.6×10-11](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9aca1772-1e0c-4e24-86a8-736d39b6760d%2F0db003b7-1afa-440a-ba2b-006ff42c140d%2Fcbku5l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 24.4 mL sample of 0.2124 M hydrotelluric acid, H₂Te, is titrated with 0.2124 M potassium
hydroxide.
What is the pH after 12.2 mL, 24.4 mL, 36.6 mL and 48.8 mL of KOH have been added?
step mL KOH added pH
1
12.2
24.4
36.6
48.8
Not submitted
2
3
4
second ionization constants for H₂Te are 2.3x10-3 and 1.6×10-11
Expert Solution
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Step 1
H2Te is a diprotic acid with Ka1 = 2.3*10-3 and Ka2 = 1.6*10-11
The dissociation equations are:
H2Te(aq) HTe-(aq) + H+(aq) ; pKa1 = -log(Ka1) = - log(2.3*10-3) = 2.64
HTe-(aq) Te2-(aq) + H+(aq) ; pKa2 = -log(Ka2) = - log(1.6*10-11) = 10.8
potassium hydroxide, KOH is a monoacidic base.
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