A 23 factorial design was used to develop a nitride each process on a single-wafer plasma etching tool Each factor is run at two levels, and the design is replicatedtwice. The response variable is the etch rate for silicon nitride. The etch rate data are shown below. Using the totals under the treatment combinations, determinethe factor effect of AC. Answer in 3 decimal places.Coded FactorsEtch RateRun123456785.625A-11-11-11-11B-1-111-1-111C-1-1-1-11111Replicate 1 Replicate 25506046696506016351052633642103774910757298681063860Total(1) = 11541319ab= 1234ab = 1277c = 2089ac = 1617bc= 2178abc = 1589=

Given information: Design applied : 23 factorial design To calculate : Effect of AC factor

Answered: A 23 factorial design was used to…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter1: Variables, Expressions, And Integers

Section1.5: Adding Integers

Problem 45E

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Reter to the mensured systolic and diastolic biood pressure mensurements of 40 andomty seiected meies and test the caimthet among men, there isa comeiation betveen systolie biood pressure and diestolic Diood pressure. Test for rank comreiation with a 0.05 sgnifcance level m Click the icon to view the blood pressure deta for men. Determine the nul and stemetive hypotheses for this test Choose the comect ansver below OA M0 O. M0 OD. HA0 Determine the coreietion coefficient -O Round to mree decimal piaces as nences) Derermine the ortical values of the comeistion coeftcient. Round to three decimal pisces as neeses. Usea comma to secarte anses as neeses) Chocse he comect enser below OA Faltoreject the nul typothesis. There is sufcient evidence to support the caimthet thereisa comiation beteen systolic and diastolic biood pressure in men. OB Reecthe nul hypothesis There is sufcient evidence to support the cam thet there is comeistion betveen systolic and diestolic biood pressure in men. OC.…
can you make those to Anova Test?Control: 10.3cm, 19.5cm, 19.8cm Experimental for 1.25ml: 18cm, 18cm (2 plants) Experimental for 2.5ml: 9cm (1 plant) Experimental for 5ml: 10.2cm, 14.1cm (2 plants) This is the result for our leaves length: Control: 4.20 cm, 4 cm, 3.7 cm , 2cm, 2.1cm, 2.1cm, 5.5cm, 5.1cm, 5.8cm, 6.1cm, 6m, 7.1cm, 7.1cm, 6.2cm, 6.6cm, 6.5cm, 2.5 cm, 16cm, 1.5cm Experimental for 1.25ml: 5.4cm, 4.5 cm, 4.5 cm, 6.5 cm, 6.3cm, 6.2cm, 1.9cm, 1.5cm, 1.4cm, 5.3cm, 5.8cm, 5.7cm, 6.2cm, 6.3cm, 6cm, 3.3 cm, 1.6cm, 2 cm (17 leaves) Experimental for 2.5ml: 4cm,3cm, 3cm (3 leaves) Experimental for 5ml: 5.4cm,5.7cm, 4.8cm, 4.7cm, 2.6cm, 2.5cm, 2.1cm ( 7 leaves)
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Hypothesis: H0: μd=0Ha: μd≠0 Using output Test statistics : t=0.134P value=0.897 Degrees of freedom (df): df=7 Level of significance: α=0.05 Decision: P value > 0.05 thus we fails to reject null hypothesis. Question a)Write a report summarizing your findings. When writing the report consider that medical staff estimate that a difference of 4.5 microns or more could impact on their ability to interpret eye pressure correctly. b) Define for the hypothesis stated in part b) what a type 1 error and type 2 error would mean. Is it possible…
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Q) If a participant has the same corneal thickness in their normal eye as the eye with Glaucoma, what would be the value for difference: measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma.
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Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Q)Conduct a hypothesis test to determine if there is sufficient evidence to conclude that corneal thickness is different in normal eyes compared to eyes with glaucoma? Write up your results using the 8 steps.
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