A 2200-kg sport utility vehicle traveling at 90 km/h can be stopped in 0.19 s if it hits concrete wall. Assume a 60 kg person was in the car that hit this wall. The velocity of the person equals that of the car both before and after the crash, and the velocity changes in 0.19 s. (a) What is the average force exerted on the person? N (in a direction opposite to the initial motion) (b) Some people think that they can stop themselves rushing forward by putting their hands on the dashboard. Find the mass of the object that has a weight equal to the force you just calculated. kg Could you lift such a mass? Are you strong enough to stop yourself with your arms?
A 2200-kg sport utility vehicle traveling at 90 km/h can be stopped in 0.19 s if it hits concrete wall. Assume a 60 kg person was in the car that hit this wall. The velocity of the person equals that of the car both before and after the crash, and the velocity changes in 0.19 s. (a) What is the average force exerted on the person? N (in a direction opposite to the initial motion) (b) Some people think that they can stop themselves rushing forward by putting their hands on the dashboard. Find the mass of the object that has a weight equal to the force you just calculated. kg Could you lift such a mass? Are you strong enough to stop yourself with your arms?
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Introduction:
We are given mass of car. We are also given mass of person. We are given initial and final velocity of person. We are also given time taken for this change in velocity. We first find force acting on person. We then find mass corresponding to this force.
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