• A 220-V shunt motor whose magnetization curve isgiven below, runs at a speed of 1200 rpm. The field-winding resistance is 40 N. Determine the resistancethat must be inserted in series with the field windingto increase the speed to 1800 rpm at no load (70 ).If (A): 1 2 3 4Op (mWb): 4.5 8 10 115 5 611.6 12.2

Answered: Image /qna-images/answer/4f2eeacb-0031-4ac9-b6ff-c32c17c230e0.jpg

Answered: • A 220-V shunt motor whose…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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3. A 4 pole, 250 dc shunt motor has a lap connected armature with 960 conductors. The flux per pole is 2 x 102Wb. Calculate the torque developed by the armature and the useful torque in N-m when the current taken by the motor is 30A. The armature resistance is 0.12 ohm and the field resistance is 125ohm. The rotational losses amount to 825W
Q2. A 230 V single-phase induction motor, 50 Hz, has the following winding impedances (at rest): Zm=28 <70° Q. Za=42 <45°Q A) Calculate the input current at start-up. B) Obtain the amount of capacitor in series with the auxiliary winding for which the torque Maximum startup. Then compare the input current, auxiliary winding current and torque all at start-up in two modes with and without starter capacitor.
Developed torque??
22. A) Why is the power factor of a lightly loaded 3-phase squirrel-cage induction motor very low? a) most of the power supplied to the motor at light loads is magnetization or inductive power b) most of the power supplied to the motor at light loads is resistive power c) most of the power supplied to the motor at light loads is capacitive power d) none of the above B) What happens to the power factor as load is increased on the motor? a) the power factor increases b) the power factor deceases c) remains the same
Q4) What is the effect in series motor if you assume V = Eb , with low resistance fielding winding ? a) b) The given information about series motor on full – load (with that the flux is proportional to the field current) is a ) takes ( 78A) and runs at (850 r.p.m) , the series winding resistance is (0.04 2) , with diverter in parallel with the field winding is a (0.18 2) and the armature resistance is (0.09 S2). ( 220 V Neglected the iron, friction and windage losses. Determine the efficiency , speed when developing full load torque ,the maximum efficiency .
A 400 V, 50 Hz 30 hp, three-phase induction motor is drawing 50 A current at 0.8 power factor lagging. The stator and rotor copper losses are 1.5 kW and 900 W respectively. The friction and windage losses are 1050 W and the core losses are 1200 W. The air-gap power of the motor will be
On full-load a 300 V series motor takes 90A and runs at 15 rev/s. The armature resistance is 0.1 ohm and the series winding resistance is 50 m.Determine the speed when developing full load torque but with a 0.2 ohm diverter in parallel with the field winding. (Assume that the flux is proportional to the field current.
Reducing the supply voltage so that Vnew = Vold / V3 reduces the maximum torque of the motor so that Tmaxnew= ...Tmaxold . * .... ...
A 250 V DC shunt motor runs at 950 rpm and takes a line current of 55A.Find the resistance to be added to the field circuit to increase the speed 1200 rpm at an armature current of 75A.Take magnetic flux proportional to field current. Armature resistance is 0.1 ohm and field winding resistance is 125 ohms.
a 220 V dc shunt motor has armature resistance 0.23 ohm, on load it takes armature current 40 A and turnes at 720 rpm, if the flux of motor is reduced by 10% without changing the load torque . Find the new speed of the motor.
A 3 phase, 1500 rpm, 2200 V, star connected synchronous motor has an impedance of 0.4+j90 per phase. At some excitation 2900 V is induced in the armature. Find the maximum torque developed by motor before the motor breaks out of synchronism. Also find the load angle this time.

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