A 22.6 L tank of nitrogen gas is at 24.0°Cand 1.5 atm. the temperature stays at 24.0 °C and the volume is compressed to 12.4 L, what is the new pressure? atm
A 22.6 L tank of nitrogen gas is at 24.0°Cand 1.5 atm. the temperature stays at 24.0 °C and the volume is compressed to 12.4 L, what is the new pressure? atm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
A 22.6 L tank of nitrogen gas is at 24.0°C and 1.5 atm. If the temperature stays at 24.0°C and the volume is compressed to 12.4 L, what is the new pressure?
**Given:**
- Initial Volume (V₁) = 22.6 L
- Initial Pressure (P₁) = 1.5 atm
- Final Volume (V₂) = 12.4 L
- Temperature (T) = 24.0°C (constant)
**Question:**
What is the new pressure (P₂)?
**Solution:**
[ **Box for answer** ] atm
**Explanation:**
To find the new pressure, we can use Boyle’s Law, which states that for a given amount of gas at constant temperature, the pressure and volume are inversely proportional. The formula is:
\[ P₁V₁ = P₂V₂ \]
Solve for \( P₂ \):
\[ P₂ = \frac{P₁V₁}{V₂} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b3e0c59-cf7b-4376-aa74-257aeab50c9a%2F505cfe37-efac-4b10-aa55-4171838a4726%2Fulgb23t_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A 22.6 L tank of nitrogen gas is at 24.0°C and 1.5 atm. If the temperature stays at 24.0°C and the volume is compressed to 12.4 L, what is the new pressure?
**Given:**
- Initial Volume (V₁) = 22.6 L
- Initial Pressure (P₁) = 1.5 atm
- Final Volume (V₂) = 12.4 L
- Temperature (T) = 24.0°C (constant)
**Question:**
What is the new pressure (P₂)?
**Solution:**
[ **Box for answer** ] atm
**Explanation:**
To find the new pressure, we can use Boyle’s Law, which states that for a given amount of gas at constant temperature, the pressure and volume are inversely proportional. The formula is:
\[ P₁V₁ = P₂V₂ \]
Solve for \( P₂ \):
\[ P₂ = \frac{P₁V₁}{V₂} \]
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