A 2020 Pew Research poll found that 65% of U.S. adults believe that President Donald Trump was too slow tomake major steps to stop the spread of the coronavirus. Let's assume that 0.65 is the population proportion.Suppose random samples of 150 U.S. adults are randomly selected, and the proportion of each sample isfound.What is the probability that a randomly selected sample proportion will be greater than 0.69? Round thestandard error to 3 decimal places and your final answer to two decimal places.

Answered: A 2020 Pew Research poll found that 65%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A racing car consumes a mean of 103 gallons of gas per race with a variance of 36. If 38 racing cars are randomly selected, what is the probability that the sample mean would be greater than 101.5 gallons? Round your answer to four decimal places.
A large tank of fish from a hatchery is being delivered to a lake. The hatchery claims that the mean length of fish in the tank is 15 inches, and the standard deviation is 4 inches. A random sample of 26 fish is taken from the tank. Let x be the mean sample length of these fish. What is the probability that x is within 0.5 inch of the claimed population mean?
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The median annual cost of auto insurance is $ 939 (According to DACO). Suppose the standard deviation is o = $ 241. What is the probability that in a simple random sample of auto insurance policies the sample mean differs more than $ 70.42 from the population mean if the sample size is 45? You must calculate the probability that the difference between the average cost in the sample and the average annual cost do not differ by $ 70.42. Find the probability that P (\ µ - š | 0) = P (-70.42 H-iS 70.42) Select one: a. The probability is 99% that the auto policy will not differ by $ 70.42 from the average annual cost. b. The probability is 50% that the auto policy will not differ by $ 70.42 from the average annual cost. c. The probability is 80% that the auto policy will not differ by $ 70.42 from the average annual cost. d. The probability is 70% that the auto policy will not differ by $ 70.42 from the average annual cost. e. The probability is 95% that the auto policy will not differ by $…
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