A 2004 Prius with a 150-lb driver and no passengers weighs 3071 lb. The car is initially at rest. Starting at t = 0, a net horizontal force Fx(t) in the +x direction is applied to the car. The force as a function of time is given in (Figure 1). The horizontal parts on the graph correspond to 7500 N and 3500 N. For the time interval t = 0 to t = 4.50 s, what is the impulse applied to the car? What is the speed of the car at t = 4.50 s? At t = 4.50 s, the 3500-N net force is replaced by a constant net braking force Bx = -5240 N . Once the braking force is first applied, how long does it take the car to stop? How much work must be done on the car by the braking force to stop the car? What distance does the car travel from the time the braking force is first applied until the car stops?
A 2004 Prius with a 150-lb driver and no passengers weighs 3071 lb. The car is initially at rest. Starting at t = 0, a net horizontal force Fx(t) in the +x direction is applied to the car. The force as a function of time is given in (Figure 1). The horizontal parts on the graph correspond to 7500 N and 3500 N. For the time interval t = 0 to t = 4.50 s, what is the impulse applied to the car? What is the speed of the car at t = 4.50 s? At t = 4.50 s, the 3500-N net force is replaced by a constant net braking force Bx = -5240 N . Once the braking force is first applied, how long does it take the car to stop? How much work must be done on the car by the braking force to stop the car? What distance does the car travel from the time the braking force is first applied until the car stops?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 2004 Prius with a 150-lb driver and no passengers weighs 3071 lb. The car is initially at rest. Starting at t = 0, a net horizontal force Fx(t) in the +x direction is applied to the car. The force as a function of time is given in (Figure 1). The horizontal parts on the graph correspond to 7500 N and 3500 N. For the time interval t = 0 to t = 4.50 s, what is the impulse applied to the car? What is the speed of the car at t = 4.50 s? At t = 4.50 s, the 3500-N net force is replaced by a constant net braking force Bx = -5240 N . Once the braking force is first applied, how long does it take the car to stop? How much work must be done on the car by the braking force to stop the car? What distance does the car travel from the time the braking force is first applied until the car stops?
Transcribed Image Text:The graph illustrates the force \( F_x \) in newtons (N) as a function of time \( t \) in seconds (s).
Key points from the graph:
- **Time Range and Force Values:**
- From 0 to 1.5 seconds, the force is constant at 8000 N.
- From 1.5 to 3 seconds, the force linearly decreases to 4000 N.
- From 3 to 4 seconds, the force continues to decrease, reaching 3000 N.
- From 4 to 5 seconds, the force remains constant at 4000 N.
- **Axes Details:**
- The horizontal axis represents time, ranging from 0 to 5 seconds.
- The vertical axis represents the force, ranging from 0 to 8000 N.
This data can be used to analyze how the force changes over the given time period and might represent a scenario in mechanics where force adjustments are being made.
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Step 1: Determine the given data:
VIEWStep 2: The impulse applied to the car for the time interval t = 0 to t = 4.50 s:
VIEWStep 3: The speed of the car at t = 4.50 s
VIEWStep 4: Once the braking force is first applied, how long does it take the car to stop
VIEWStep 5: work must be done on the car by the braking force to stop the car:
VIEWStep 6: Distance does the car travel from the time the braking force is first applied until the car stops
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