A 20.00 mL solution of 0.00500 M Sn² in 1 M HCI was titrated with 0.0200 M Cet to give Sn and Ce³. Calculate the potential at the following volumes of Ce: 1.00, 5.00, 9.50, 10.00, and 12.00 mL. HINT: Stoichiometry is important in this reaction. 1.47 V (in HCI) Ce+ e-Ce³- Sn** +2e- → Sn² E° Eº = 0.139 V

A 20.00 mL solution of 0.00500 M Sn² in 1 M HCI was titrated with 0.0200 M Cet to give Sn and Ce³. Calculate the potential at the following volumes of Ce: 1.00, 5.00, 9.50, 10.00, and 12.00 mL. HINT: Stoichiometry is important in this reaction. 1.47 V (in HCI) Ce+ e-Ce³- Sn** +2e- → Sn² E° Eº = 0.139 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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