Answered: A 20.0-m tall hollow aluminum flagpole… | bartleby

Related questions

Question

A 20.0-m tall hollow aluminum flagpole is equivalent in strength to a solid cylinder 4.00 cm in diameter. A strong wind bends the pole much as a horizontal force of 1200 N exerted at the top would.

f = 1200 N

How far to the side does the top of the pole flex in mm? Assume the shear modulus is 2.5x10¹⁰ N/m².

ΔL =

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Assume that if the shear stress in steel exceeds about 4.00 x 108 N/m², the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 1.40 cm in diameter. IN (b) Determine the shearing force necessary to punch a 1.25-cm-diameter hole in a steel plate 0.550 cm thick. N
A plank 2.00 cm thick and 16.3 cm wide is firmly attached to the railing of a ship by clamps so that the rest of the board extends 2.00 m horizontally over the sea below. A man of mass 67.7 kg is forced to stand on the very end. If the end of the board drops by 5.40 cm because of the man's weight, find the shear modulus of the wood. 75376.05
A steel wire, 3.0 m long, has a diameter of 1.0 mm. If a 10 kg load is hung from the wire how far will it stretch? Young's modulus for steel is 2.0 × 10^11 pa
Consider a square-faced beam supporting a section of a building. a) Before installation, the length of the beam is found to be l0 = 15.02 m (figure a). After installation and construction, the length is remeasured and found to be l = 14.98 m (figure b). Determine Young's Modulus Y in N/m2 for the beam if it supports a mass m = 35000 kg and has a side length d = 1.9 m. b) Suppose that after the beam is installed it needs to be repaired. The weight it supports is removed and replaced with a new mass m2 (figure c). After the new mass is supported, the side length is remeasured and found to be larger with a difference of Δd. Assuming that this side length deformation is uniform and small, write an expression for determining Poisson's ratio v for this beam if its Young's modulus Y is known.
B8
What hanging mass will stretch a 2.2-m-long, 0.34 mm - diameter steel wire by 1.2 mm? The Young's modulus of steel is 20×10^10N/m2. Express your answer in kilograms.
Masses M1 and M2 are supported by wires that have equal lengths when unstretched. The wire supporting M1 is an aluminum wire 1.35 mm in diameter, and the one supporting M2 is a steel wire 0.4 mm in diameter. What is the ratio M1/M2 if the two wires stretch by the same amount? Young’s modulus for aluminum is 7 × 10^10 N/m^2and for steel 2 × 10^11 N/m^2. *