A 20.0 kg box slides up a 12.0 m long incline at an angle of 30.0 degrees with the horizontal. A force of 150 N is applied to the box to pull it up the incline. The applied force makes an angle of 10.0 degrees to the incline. What is the work done by the applied force? Multiple Choice 1,870 J 1,770 J O 1,500 J O 1,450J 1,380 J

College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A 20.0 kg box slides up a 12.0 m long incline at an angle of 30.0 degrees with the horizontal. A force of 150 N is applied to the box to pull it up the incline. The applied force makes an angle of 10.0 degrees to the incline. What is the work done by the applied force?

**Multiple Choice Options:**

- ○ 1,870 J
- ○ 1,770 J
- ○ 1,500 J
- ○ 1,450 J
- ○ 1,380 J

**Explanation:**

To solve this problem, we need to calculate the work done by the applied force. The formula for work done is:

\[ W = F \cdot d \cdot \cos(\theta) \]

Where:
- \( W \) is the work done
- \( F \) is the magnitude of the force
- \( d \) is the distance over which the force is applied
- \( \theta \) is the angle between the force and the direction of motion

Plug in the given values:
- \( F = 150 \, \text{N} \)
- \( d = 12.0 \, \text{m} \)
- \( \theta = 10.0^\circ \)

Calculate by substituting these values into the formula.
Transcribed Image Text:**Problem Statement:** A 20.0 kg box slides up a 12.0 m long incline at an angle of 30.0 degrees with the horizontal. A force of 150 N is applied to the box to pull it up the incline. The applied force makes an angle of 10.0 degrees to the incline. What is the work done by the applied force? **Multiple Choice Options:** - ○ 1,870 J - ○ 1,770 J - ○ 1,500 J - ○ 1,450 J - ○ 1,380 J **Explanation:** To solve this problem, we need to calculate the work done by the applied force. The formula for work done is: \[ W = F \cdot d \cdot \cos(\theta) \] Where: - \( W \) is the work done - \( F \) is the magnitude of the force - \( d \) is the distance over which the force is applied - \( \theta \) is the angle between the force and the direction of motion Plug in the given values: - \( F = 150 \, \text{N} \) - \( d = 12.0 \, \text{m} \) - \( \theta = 10.0^\circ \) Calculate by substituting these values into the formula.
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