A 20 cm diameter and 20 turn circular coil is located in the xy-plane, and each wire of the coil carries a current of 2,0 A in the counter-cl ockwise direction. An external magnetic field B = (0.55î + 0.60ĵ – 0.65k) passes through the coil. Find the coil's magnetic moment i (in units of A m?), the torque (in units of Nm) acting on the coil due to the external magnetic field, and the potential energy of the coil within the field (in units of Joule). Take n = 3. a) i = 1.2k; † = [0.72î – 0.66ĵ]; U = –0.78 b) i = 1.2(-j); † = [0.78î + 0.66k); U = 0.72 c) i = 1.2(-i); † = [-0.78ĵ – 0.72]; U = 0.66 d) i = 1.2k; † =[-0,72î + 0.66f]; U = 0.78 %3D e) i = 1.2j; † = [-0.78î – 0.66k]; U = –0.72

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A 20 cm diameter and 20 turn circular coil is located in the xy-plane, and each
wire of the coil carries a current of 2,0 A in the counter-clockwise direction. An
external magnetic field B = (0.55î + 0.60ĵ – 0.65k) passes through the coil.
Find the coil's magnetic moment i (in units of A m²), the tor que (in units of Nm)
acting on the coil due to the external magnetic field, and the potential energy of
the coil within the field (in units of Joule). Take n = 3.
a) i = 1.2k; i = [0.72î – 0.66j]; U = –0.78
b) i = 1.2(-j); i = [0.78î + 0.66k]; U = 0.72
c) i = 1.2(-1); i =[-0.78ĵ – 0.72k]; U = 0.66
d) i = 1.2k; i =[-0,72î + 0.66f]; U = 0.78
%3D
e) i = 1.2j; i = [-0.78î – 0.66k]; U = -0.72
Transcribed Image Text:A 20 cm diameter and 20 turn circular coil is located in the xy-plane, and each wire of the coil carries a current of 2,0 A in the counter-clockwise direction. An external magnetic field B = (0.55î + 0.60ĵ – 0.65k) passes through the coil. Find the coil's magnetic moment i (in units of A m²), the tor que (in units of Nm) acting on the coil due to the external magnetic field, and the potential energy of the coil within the field (in units of Joule). Take n = 3. a) i = 1.2k; i = [0.72î – 0.66j]; U = –0.78 b) i = 1.2(-j); i = [0.78î + 0.66k]; U = 0.72 c) i = 1.2(-1); i =[-0.78ĵ – 0.72k]; U = 0.66 d) i = 1.2k; i =[-0,72î + 0.66f]; U = 0.78 %3D e) i = 1.2j; i = [-0.78î – 0.66k]; U = -0.72
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