Answered: A 2.5 cm-long horizontal wire segment… | bartleby

Related questions

Question

A 2.5 cm-long horizontal wire segment has mass 0.15 g and carries a current
sufficiently large that it levitates when the segment is in a region of B field
upward with magnitude 1.5 T. The current is passed to the segment that is in
the magnetic field by way of massless electrical leads. What is the magnitude
of the current that the wire carries?

Expert Solution

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

a charged particle enters a mass spectrometer with uniform magnetic field B= .60 T pointing into the page. if the particle has mass m= 3.2 x10^-12 kg and is travelling at a speed of 5.0 x 10^5 m/s, then it is seen to curve in the magnetic field as shown and strikes a detector d=12.0 cm away from the point where it entered the mass spectrometer. what is the charge on the particle? a) +44 microC b) -44 microC c) -68 microC d) +68 microC
A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.84 T. How much time does it take for the particle to complete one revolution?
A magnetic field has a magnitude of 0.0014 T, and an electric field has a magnitude of 3.5 × 103 N/C. Both fields point in the same direction. A positive 1.7-μC charge moves at a speed of 2.8 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number 1+1 P90⁰ Units BA
A current-carrying wire of length 0.5 meters is placed perpendicular to a magnetic field of 0.4 Tesla. If the current flowing through the wire is 3 Amperes, what is the magnitude and direction of the magnetic force acting on the wire?
A powerful, superconductive wire carries a 5000A current directly out of this screen. An electron is travelling parallel to the wire with a speed of 5E8 m/s, in the same direction as the current. the electron is 50.0 (micrometer) to the right of the wire. A) What is the magnitude and direction of the Magnetic field due to the superconductor at the location of the electron? B) What is the magnitude and direction of the force acting on the electron due to the superconductor's magnetic field?
A beam of electrons is simultaneously influenced by an homogeneous electric field of 15600 V/m and by a homogeneous magnetic field of 4.62 x 10-3 T. Assume that both fields are perpendicular to the electron beam and to each other. Both fields have to be oriented such that they produce no deflection of the electron beam. a) Draw the relative orientations of the vectors v, E, and B and also the forces of FE and FB .b) Determine the speed of the electrons such that there is no deflection of the electron beam. c) When the electric field is switched off, what is the radius and the period of the electron orbit?
When a proton has a velocity of (2i+8j)*10^6 m/s , it experiences a force of -1.6*10^-13k N. . In a second experiment with the same B field, the particle is moving along the + z-axis and under these new conditions it experiences a force along the + x-axis . What is the magnetic field? answer should be in (i,j,k)
In 1897, the English physicist J. J. Thomson used crossed electric and magnetic fields to measure the charge to mass ratio of electrons. (A) Determine the ratio in SI units. (B) Determine the charge to mass ratio of a proton. (C) In one experiment, electrons are accelerated to speed v by an electric field E, and are then deflected by a magnetic field B. For the parameters given below, calculate the radius of the circular arc in the magnetic field. electric field = = 2.85 kV/cm; distance of the acceleration = 0.84 m; magnetic field = 0.08 T ]